I need the answers for the attachments please.

How can one tell if an object can absorb light or not? How about transmit? Thank you!

kondaur [170]

Absorb:
Shine a light with known intensity into the object.
Measure the intensity of the light that comes out.
Any light that goes in but doesn't come out the other side
was absorbed by the object.
(Note: You also need to be aware of any light that bounces back from
the first side without entering the object. That light is reflected from it,
and can't be expected to show up at the other side.)

Transmit:
Any light that goes in and DOES come out the other side
was transmitted by the object.

4 0

3 years ago

5

Ronch [10]

Answer:

Current in a parallel circuit = 0.61 amps (Approx)

Explanation:

Given:

Voltage V = 6 volt

Two resistors = 17.2 , 22.4 in parallel circuit

Find:

Current in a parallel circuit

Computation:

1/R = 1/r1 + 1 / r2

1/R = 1/17.2 + 1 / 22.4

R = 9.73 ohms (Approx)

Current in a parallel circuit = V / R

Current in a parallel circuit = 6 / 9.73

Current in a parallel circuit = 0.61 amps (Approx)

4 0

3 years ago

Connecting many devices in a single socket does not affect the flow of current in a

eimsori [14]

Answer:- False

Explanation:-

False because it can leads to overloading and further to short circut.

7 0

3 years ago

For each of the following velocity vectors, give the vector component, the scalar component, and the magnitude. (a) v = 48.0j m/

Oduvanchick [21]

Obtaining the component part of the letter 'i' warns that it is the velocity is oriented on the X axis. At the same time the numeric part, in this particular case will represent the scalar part and therefore the magnitude of the vector.

The velocity is

$\vec{v} = 48.0\hat{i} \text{ m/s }$

The vector component of the velocity is

$v_x = 48.0m/s$

The scalar component of the velocity is

$v = 48.0m/s$

The magnitude of the velocity is

$v = 48.0m/s$

3 0

4 years ago

Something is thrown in the air and 5.35 seconds later it lands on something 2.1 meters from the ground. How fast was it thrown u

UNO [17]

Answer:

26.6 m/s

Explanation:

Given:

Δy = 2.1 m

t = 5.35 s

a = -9.8 m/s²

Find: v₀

Δy = v₀ t + ½ at²

(2.1 m) = v₀ (5.35 s) + ½ (-9.8 m/s²) (5.35 s)²

v₀ = 26.6 m/s

5 0

3 years ago