Cylinder (A):
-Surface area: adding all areas of all faces of the shape.
*10 x 6= 60m^3
*3.14 x 3^2 = 28.274 m^2. Then We times it by 2 since we have 2 circles. Which equals to 56.55m^2
Total surface area: 60 + 56.55 = 116.55m^2
-Volume: 3.14 x r^2 x h, then substitute.
*3.14 x 3^2 x 10 = 282.74m^3
(B):
-surface area:
*7 x 11= 77
*5 x 11 = 55
*11 x 11 = 121
*7 x 5 = 35/2 = 17.5 > then again we times it by 2 cuz we have 2 triangles. Which equals to 35.
Total surface area: 77 + 55 + 121 + 35 = 288 cm^2
-Volume:
*7 x 5 x 11 = 385 cm^3
Make sure to check the units!!!
Hope this helped :)
Answer:
The distance between the points (2, 7) and (2, 15) is 8.
Step-by-step explanation:
<u>What is the Distance between Two Points?</u>
For any two points there is exactly one line segment connecting them. The distance between two points is the length of the line segment connecting them. Note that the distance between two points is always positive. Segments that have equal length are called congruent segments.
How to Solve:
Formula:
Putting Values:
![=\sqrt{(2-2)^2+(15-7)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%282-2%29%5E2%2B%2815-7%29%5E2%7D)
![=\sqrt{(0)^2+(8)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%280%29%5E2%2B%288%29%5E2%7D)
![=\sqrt{0+64}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B0%2B64%7D)
![=\sqrt{64}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B64%7D)
![=8](https://tex.z-dn.net/?f=%3D8)
R^2=(x-6)^2+(y-4)^2
r^2=(6-2)^2+(4-1)^2, r^2=16+9=25
(x-6)^2+(y-4)^2=25
Answer: The answer is (B) 2x + 3(3x – 5) = 51
.
Step-by-step explanation: We are given three options and we are to select which choice shows the result of substituting 3x – 5 into the second equation for y.
So, y = 3x - 5.
Since the standard form of a linear equation i two variables is ax + by = c, so the second equation as given in the options must be of the form 2x + 3y = 51.
If we substitute y = 3x - 5, then this equation becomes
2x + 3(3x - 5) = 51.
Thus, (B) 2x + 3(3x – 5) = 51 is the correct option.