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True [87]
3 years ago
9

Find x. Round to the nearest tenth if necessary.a 4 b 5 c 6 d 3

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0
The answer is B. 5

6+2=8

3+5=8
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The value of (2 x 10^4) + (9 x 10^4) - (3 x 10^3) in scientific notation?
Tcecarenko [31]

Answer:

1.07 X 10^5

Step-by-step explanation:

8 0
4 years ago
I need help to find the square units of this triangle
ipn [44]

Answer:

24square unit

Step-by-step explanation:

triangle area=1/2.b.h

=1/2.8.6=24

8 0
2 years ago
In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B, where f(x,
Tomtit [17]

To approximate the volume with 8 boxes, we have to split up the interval of integration for each variable into 2 subintervals, [0, 1] and [1, 2]. Each box will have midpoint m_{i,j,k} that is one of all the possible 3-tuples with coordinates either 1/2 or 3/2. That is, we're sampling f(x,y,z)=\cos(xyz) at the 8 points,

(1/2, 1/2, 1/2)

(1/2, 1/2, 3/2)

(1/2, 3/2, 1/2)

(3/2, 1/2, 1/2)

(1/2, 3/2, 3/2)

(3/2, 1/2, 3/2)

(3/2, 3/2, 1/2)

(3/2, 3/2, 3/2)

which are captured by the sequence

m_{i,j,k}=\left(\dfrac{2i-1}2,\dfrac{2j-1}2,\dfrac{2k-1}2\right)

with each of i,j,k being either 1 or 2.

Then the integral of f(x,y,z) over B is approximated by the Riemann sum,

\displaystyle\iiint_B\cos(xyz)\,\mathrm dV\approx\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos m_{i,j,k}\left(\frac{2-0}2\right)^2

=\displaystyle\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos\frac{(2i-1)(2j-1)(2k-1)}8

=\cos\dfrac18+3\cos\dfrac38+3\cos\dfrac98+\cos\dfrac{27}8\approx\boxed{4.104}

(compare to the actual value of about 4.159)

4 0
3 years ago
Estimate square root of 12 to the nearest tenth.<br><br> A 4.5<br> B 3.9 <br> C 4.1<br> D 3.5
Sholpan [36]

Answer:

  3.5

Step-by-step explanation:

As a first approximation of the square root, you can look at the integers relating the given number to the next lower square number. The next lower square number is 3^2 = 9.

  12 = n^2 +r = 3^2 +3 . . . . . n = 3, r = 3

The approximate square root is ...

  n +r/(2n+1) = 3 +3/7 ≈ 3.429

This value tends to be a little low. Alternatively, the root can be estimated as ...

  n +r/(2n) = 3 +3/6 = 3.5

This value tends to be a little high.

A reasonable estimate of √12 is 3.5.

__

Of course, your calculator can tell you instantly that the root is about 3.464102, close to 3.5.

_____

<em>Additional comment</em>

The relation we used above simplifies the work of linear interpolation between the points (9, 3) and (16, 4) on the square root curve. For some n between 9 and 16, the interpolated root value r would be found from ...

  (n -9)/(16 -9) = (r -3)/(4 -3)

  (n -9)/7 = (r -3)/1

  r = 3 +(n -9)/7 = 3 +(12 -9)/7 = 3 +3/7 . . . . as above

Note that "r" is used for "root" in this discussion. In the above answer, "r" is used for "remainder."

6 0
3 years ago
What is the domain of f(x)<br> {x|-4<br> {x|-3<br> {x|1<br> {x|2
katrin [286]
The answer is 3 I think
8 0
3 years ago
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