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hammer [34]
2 years ago
7

Which number sentence is not true?

Mathematics
1 answer:
melomori [17]2 years ago
5 0

Answer:

D

Step-by-step explanation:

The absolute value of a number is the actual distance of the number from zero. So, it is always a positive number. No negative value.

A) I -4.5I = 4.5    TRUE

B) I 0I  < I -45I   TRUE  

Reason: 0 < 45

C) I 45 I > 0         TRUE

D) I4.5 I > I - 45 I     FALSE

Reason: 4.5is not greater than 45

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Step-by-step explanation:

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Ron has $49.Matt has $19 more than Ron.Naomi has $12 less than Matt.How much money do they have altogether?
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d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

3 0
3 years ago
A company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that
kondaur [170]

Answer:

Probability that the company wins project A or project B is 0.50.

Step-by-step explanation:

We are given that a company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that the company wins project B is 0.25.

Also, Winning project A and winning project B are independent events.

Let the Probability of winning project A = P(A) = 0.40

            Probability of winning project B = P(B) = 0.25

<u>Now, as we know that ;</u>

Probability that the company wins project A or project B = P(A \bigcup B)

              P(A \bigcup B) = P(A) + P(B) -  P(A \bigcap B)

So, we have to find the value of Probability of winning project A and B, i.e;

P(A \bigcap B)

<em>Since, we are given that Winning project A and winning project B are independent events which means when this condition is given then;</em>

                    P(A \bigcap B) = P(A) \times P(B)

                                    = 0.40 \times 0.25 = 0.10

Now, Probability that the company wins project A or project B is given by;

                 P(A \bigcup B) = P(A) + P(B) -  P(A \bigcap B)  

                                  = 0.40 + 0.25 - 0.10

                                  = 0.65 - 0.10 = 0.55

Hence, probability that the company wins project A or project B is 0.50.

3 0
3 years ago
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