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3 years ago

Pls anwser this question pls it’s easy math I really need it look at the pic

Mathematics

1 answer:

attashe74 [19]3 years ago

6 0

Answer:

I beleive the answer is D

Step-by-step explanation:

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Leslie determined that the system of equations below has infinitely many solutions. Is she correct?

Nookie1986 [14]

Answer:

Leslie determined that the system of equations below has infinitely many solutions. Is she correct?

x=4y-4

2x-8y=-24

A.Yes, Leslie is correct.

B. No, the solution is (-8,-24)

C. No, the solution is (0,-16)

<u>D. No, the system of equations has no solution. </u>

Step-by-step explanation:

you have to solve they as a pair of simultaneous equations and their is no solutions

if you need a more detailed explanation post the question again and i will write a detailed explanation

plz mark as brainliest

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3 years ago

Read 2 more answers

Find the value of (-1/2)³

Evgen [1.6K]

Answer:

-1/8

Step-by-step explanation:

(-1/2) ^3

(-1/2)(-1/2)(-1/2)

-1/8

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2 years ago

Anthony will be competing in a body building competition in 12 months. he initially weighs 160 pounds and by the end of 12 month

padilas [110]

He starts out with the weight of 160, at the end of those 12 months he weighs 232. if you subtract 160 and 232 the approximate rate of change should be 72

4 0

3 years ago

Can some1 help? im a little confused:(

fgiga [73]

Answer:

Step-by-step explanation:

brainly.com/question/1701683

url to the help thingy

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2 years ago

A conical water tank with vertex down has a radius of 13 feet at the top and is 21 feet high. If water flows into the tank at a

VLD [36.1K]

Answer:

$\frac{dh}{dt}\approx0.08622\text{ ft/min}$

Step-by-step explanation:

We know that the conical water tank has a radius of 13 feet and is 21 feet high.

We also know that water is flowing into the tank at a rate of 30ft³/min. In other words, our derivative of the volume with respect to time t is:

$\frac{dV}{dt}=\frac{30\text{ ft}^3}{\text{min}}$

We want to find how fast the depth of the water is increasing when the water is 17 feet deep. So, we want to find dh/dt.

First, remember that the volume for a cone is given by the formula:

$V=\frac{1}{3}\pi r^2h$

We want to find dh/dt. So, let's take the derivative of both sides with respect to the time t. However, first, let's put the equation in terms of h.

We can see that we have two similar triangles. So, we can write the following proportion:

$\frac{r}{h}=\frac{13}{21}$

Multiply both sides by h:

$r=\frac{13}{21}h$

So, let's substitute this in r:

$V=\frac{1}{3}\pi (\frac{13}{21}h)^2h$

Square:

$V=\frac{1}{3}\pi (\frac{169}{441}h^2)h$

Simplify:

$V=\frac{169}{1323}\pi h^3$

Now, let's take the derivative of both sides with respect to t:

$\frac{d}{dt}[V]=\frac{d}{dt}[\frac{169}{1323}\pi h^3}]$

Simplify:

$\frac{dV}{dt}=\frac{169}{1323}\pi \frac{d}{dt}[h^3}]$

Differentiate implicitly. This yields:

$\frac{dV}{dt}=\frac{169}{1323}\pi (3h^2)\frac{dh}{dt}$

We want to find dh/dt when the water is 17 feet deep. So, let's substitute 17 for h. Also, let's substitute 30 for dV/dt. This yields:

$30=\frac{169}{1323}\pi (3(17)^2)\frac{dh}{dt}$

Evaluate:

$30=\frac{146523}{1323}\pi( \frac{dh}{dt})$

Multiply both sides by 1323:

$39690=146523\pi\frac{dh}{dt}$

Solve for dh/dt:

$\frac{dh}{dt}=\frac{39690}{146523}\pi$

Use a calculator. So:

$\frac{dh}{dt}\approx0.08622\text{ ft/min}$

The water is rising at a rate of approximately 0.086 feet per minute.

And we're done!

Edit: Forgot the picture :)

3 0

3 years ago