The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.
<h3>Can this atrium be built in the rectangular plot of land?</h3>
The atrium with the <em>maximum allowable</em> radius (<em>R</em>), in feet, is represented in the image attached. The <em>real</em> atrium is possible if and only if the <em>real</em> radius (<em>r</em>) is less than the maximum allowable radius and therefore, the <em>real</em> volume (<em>V</em>), in cubic feet, must be less than than <em>maximum possible</em> volume (<em>V'</em>), in cubic feet.
First, we calculate the volume occupied by the maximum allowable radius:
<em>V' =</em> (8 · π / 3) · (45 ft)³
<em>V' ≈</em> 763407.015 ft³
The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium. 
To learn more on volumes, we kindly invite to check this verified question: brainly.com/question/13338592
Here the value of 3 is =3/10
Then 100 fold of 3/10=3/10*100=30
So, the number 26538,532,97436 etc. has that property.
Yes. If the side lengths are different, you can end up with different angle measurements (example: SSA~ property. You can have two sides that are the same but you can make two different triangles with those side lengths and that one angle.)
Answer:
2/3
Step-by-step explanation:
Probability is the ratio of the number of possible outcome to the number of total outcome.
Given that there are 10 balls of which 3 green, 3 red, and the rest yellow
Number of yellow balls = 10 - 3 - 3 = 4
Probability of picking a;
Green ball = 3/10
Red ball = 3/10
Yellow ball = 4/10
If two balls are picked without replacement, the probability that one is at least yellow will be
YR RY YG GY YY
= 4/10*3/9 + 3/10*4/9 + 4/10*3/9 + 3/10*4/9 + 4/10*3/9
=12/90 *5
= 2/3