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Amanda [17]
3 years ago
14

*20 points*

Mathematics
1 answer:
tresset_1 [31]3 years ago
7 0

There will be about 6.25 sheep on each acre.  

250/40 = 6.25

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A wheel has a radious of 50cm. How many times would the wheel go around if it rolled for 10km
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First you must make sure all measurements are in the same value: You can choose either cm or km

Distance = 1,000,000 cm or 10 km

Radius = 50 cm or 0.0005 km

Distance/(2πR)

1,000,000/(2π*50)

1,000,000/314.059…….

Approx = 3183.1 Rotations
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Which word best compleates the statement below look at the diagram to help
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Answer:

The answer is option B.

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Find a number You can add to 6274 so you have to regroup ones,tens, and Hundreds
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Read 2 more answers
Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

8 0
3 years ago
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