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3 years ago

20 points

Mathematics

1 answer:

tresset_1 [31]3 years ago

7 0

There will be about 6.25 sheep on each acre.

250/40 = 6.25

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Use the net to find the surface area of the prism.

Naddik [55]

286 feet; use the numbers and find the area of each rectangle, then add them all together.

3 0

3 years ago

What is ∑n=16[4(−5)n−1] equal to? Enter your answer in the box.

Cerrena [4.2K]

Step-by-step explanation:

Geometric Sequence formula for general term:

an = a1(r^n-1)

a1 = 4 × (-5)^1-1

a1 = 4

r = -5

Summation formula for geometric sequence :

Sn = a1 ( 1 - r^n / 1 - r )

...take n from the top of the summation.

= 4 ( 1 -(-5)^6 / 1 -(-5)

= -10416.

4 0

2 years ago

Can someone help me with 3 a and b?? Thank you

polet [3.4K]

M∠ADB + m∠BDC = m∠ADC [angle addition postulate]

x + x + 10 = 60
2x + 10 = 60
2x = 60 - 10
2x = 50
x = 50/2
x = 25

a
m∠ADB = x = 25°

b
m∠BDC = x + 10 = 25 + 10 = 35°

5 0

3 years ago

N Over 33 = 4 Over 11

raketka [301]

Answer:

d. n = 12

Step-by-step explanation:

n/33 = 4/11

cross-multiply:

11n = 132

divide both sides by 11:

n = 12

5 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago

*20 points*

20 points