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3 years ago

14

20 points

1 answer:

tresset_1 [31]3 years ago

7 0

There will be about 6.25 sheep on each acre.

250/40 = 6.25

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Solve log(2)(4x+8)=5

marysya [2.9K]

4x+8 = 32, 4x = 24, x = 6

6 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago

What is the surface area of this right rectangular prism? Enter your answer as a

mixas84 [53]

You will find all of the surface area of all of the sides and add them together to find the surface area of the retangular prisim. So, what I would do is the front and back are both 54, so 108. The sides are 27, so 54. The top and bottom are 18, so 36. Add them together, and you will get 198. I hope this helps.

6 0

3 years ago

H=-5 and w=2, work out the value of 4h-3w

olganol [36]

You would simply have to plug in, or substitute, the given values in the equations.

So, H=-5, W=2 and the problem is 4h-3w

To plug them in, your new equation would be 4(-5)-3(2) and simplify. So it becomes -20-6 which = -26.

And -26 would be your answer.

3 0

3 years ago

Read 2 more answers

A suitcase measures 21 inches by 16 inches. What is the length of the diagonal of the suitcase to the nearest tenth of an inch?

kap26 [50]

Answer:

Step-by-step explanation:

we have a rectangle that measure 21 inches by 16 inches

to find the rectangle(which is the hypotenuse) we will use Pythagorean theorem

c^=a^2+b^2

c^=21^2+16^2=697

c= $\sqrt697}$ =26.40 which rounded to the nearest tenth =26

7 0

2 years ago