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Olenka [21]
3 years ago
8

Pls help w work!!

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

Lets Do

\\ \sf\longmapsto p = 2(l + w) \\ \\ \sf\longmapsto l + w =  \frac{p}{2}  \\ \\ \sf\longmapsto w =  \frac{p}{2}  - l \\ \\ \sf\longmapsto  \boxed{ \bf \: w =  \frac{p - 2l}{2} }

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[20points][Precal] Find the cross product of -(3/4)V and (1/2)w if v = <-2, 12, -3> and w = <-7, 4, -6>
Lana71 [14]
\mathbf v=\langle-2,12,-3\rangle=-2\,\vec i+12\,\vec j-3\,\vec k
-\dfrac34\mathbf v=\dfrac32\,\vec i-9\,\vec j+\dfrac94\,\vec k

\mathbf w=\langle-7,4,-6\rangle=-7\,\vec i+4\,\vec j-6\,\vec k
\dfrac12\mathbf w=-\dfrac72\,\vec i+2\,\vec j-3\,\vec k

-\dfrac34\mathbf v\times\dfrac12\mathbf w=\begin{vmatrix}\vec i&\vec j&\vec k\\\frac32&-9&\frac94\\-\frac72&2&-3\end{vmatrix}
=\left((-9)\times(-3)-\dfrac94\times2\right)\,\vec i-\left(\dfrac32\times(-3)-\dfrac94\times\left(-\dfrac72\right)\right)\,\vec j+\left(\dfrac32\times2-(-9)\times\left(-\dfrac72\right)\right)\,\vec k
=\dfrac{45}2\,\vec i-\dfrac{27}8\,\vec j-\dfrac{57}2\,\vec k=\left\langle\dfrac{45}2,-\dfrac{27}8,-\dfrac{57}2\right\rangle
6 0
3 years ago
Find the areas of the sectors formed by ZDFE. Round your answers to the nealest hundredth.
Sonja [21]

Answer:

Step-by-step explanation:

Area of the sector is modeled by the expression = \frac{\theta}{360}(\pi ) r^{2}

Here, θ = central angle subtended by the arc

r = Radius of the circle

Area of the red sector = \frac{137}{360}(\pi)(28)^{2}

                                     = 937.311

                                     ≈ 937.31 m²

Therefore, area of the red sector is 937.31 m².

3 0
2 years ago
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