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velikii [3]
3 years ago
11

I got the same answer as the example

Mathematics
1 answer:
DaniilM [7]3 years ago
5 0

Answer:

17

Step-by-step explanation:

2x2=4 4-7=3 3x3=21 21-4=17

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25.7 is what percent of 141?
Lady_Fox [76]

Answer:

about 18.2%

Step-by-step explanation:

All you have to do is divide the result of the percent, so 25.7, by the total, 141.

So 25.7÷141=0.18226950354

We round it to 0.182 and multiply it by 100 to know the percent which is 18.2

7 0
4 years ago
W=<br> she suznsnsja. s<br> anna abs <br> s<br> sm
vodka [1.7K]

Answer:

-32

Step-by-step explanation:

7 0
3 years ago
An elevator has a placard stating that the maximum capacity is 1600 lb�10 passengers.​ So, 10 adult male passengers can have a m
Bezzdna [24]

Answer:

1. 0.7421 = 74.21% probability the elevator is overloaded.

2. D.​No, there is a good chance that 10 randomly selected people will exceed the elevator capacity.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 166 lb and a standard deviation of 29 lb​.

This means that \mu = 166, \sigma = 29

Sample of 10.

This means that n = 10, s = \frac{29}{\sqrt{10}}

1.The probability the elevator is overloaded is?

Probability that the sample mean is above 160 pounds, which is 1 subtracted by the p-value of Z when X = 160. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 166}{\frac{29}{\sqrt{10}}}

Z = -0.65

Z = -0.65 has a p-value of 0.2579.

1 - 0.2579 = 0.7421

0.7421 = 74.21% probability the elevator is overloaded.

2. Does this elevator appear to be​ safe?

High probability of the elevator being overloaded, so not safe. Correct answer is given by option D.

7 0
3 years ago
A mint produces 150,000 souvenir coins each year. In a random sample of 400 coins, 3 have a misprint. Predict the number of coin
Tema [17]
150,000 / 400 = 375. 375(3)= 1,125 misprints per year. hope this helps!
5 0
3 years ago
75% of what equals 48?
Alika [10]

Answer:

75 percent of 64 = 48

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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