Answer:
OPTION D
Step-by-step explanation: PLS MARK BRAINLIEST :D
Answer:
Step-by-step explanation:
For a function f to have a maximum as per derivative rule we have to have
f'(x) =0, f"(x) <0
If second derivative =0 also then it is not maximum but point of inflections
Whenever f(x) = ax^n
we have
f'(x) = 0 gives x=0 and
f"(x) = n(n-1) ax ^(n-2)
So for n greater than or equal to there cannot be any maximum
And also for a straight line
y =-4x
y'=-4 and y"-0
No maximum
So only maximum can be for a funciton of the form y = ax^2
Here we do not have that all degrees are either 1 or greater than 1.
So no maximum for any funciton.
Step-by-step explanation:
y-7/4-7=x+8/8-8
-y+7/3=0
y=7
