If x=-6 then y=54.
If x=-4 then y=51.
If x=-2 then y=48.
If x=0 then y=45.
If x=2 then y=42.
If x=4 then y=39.
If x=6 then y=36.
There are an infinite variety of pairs of numbers for 'x' and 'y'
that can make that equation true.
You can use that equation to draw a line on a graph. Then
EVERY point on the line is a solution to the equation.
'x' and 'y' don't have single values unless you have TWO equations.
Answer:
jen
Step-by-step explanation:
Jordan's total number of sit-ups
20+24+28+32= 104
Jen's total number of sit-ups
40+48+56+62=208
divide Jen's sit-ups by Jordan's sit-ups
208/104=2
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as

n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) =
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
3/10 or 0.3 or 30%
Step-by-step explanation:
Its 225/750 total students
We simplify this by dividing by 5
45/150
Divide by 5 again
9/30
Divide by 3
3/10