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vaieri [72.5K]
2 years ago
14

-Jamek made rice krispies treats to share with his friends, he gave 2/7 to Josue, 1⁄6 to

Mathematics
2 answers:
NNADVOKAT [17]2 years ago
6 0

1/8                                     ngthbg vtvt4crvg ecv ercfg bg bn

Lesechka [4]2 years ago
4 0

Answer:I might be wrong but I think it’s 1/8 sorry if wrong probably is

Step-by-step explanation:

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54 is 75% of ______________
Levart [38]

54=3x/4

18=x/4

18*4=x

72=x


6 0
3 years ago
Which equation will help susan solve her problem let x the legnth of one side of the flag
scoundrel [369]
Susan will need 3 meters of fabric
6 0
3 years ago
An insurance company states that it settles 85% of all life insurance claims within 30 days. A consumer group asks the state ins
BlackZzzverrR [31]

Using the z-distribution, it is found that since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence that the proportion is below 85%, that is:

H_0: p \geq 0.85

At the alternative hypothesis, it is tested if there is enough evidence that the proportion is below 85%, that is:

H_0: p < 0.85

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are:

p = 0.85, n = 250, \overline{p} = \frac{203}{250} = 0.812

Hence the test statistic is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.812 - 0.85}{\sqrt{\frac{0.85(0.15)}{250}}}

z = -1.68

<h3>What is the p-value and the conclusion</h3>

Using a z-distribution calculator, with a left-tailed test, as we are testing if the proportion is less than a value, and z = -1.68, the p-value is of 0.0465.

Since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

More can be learned about the z-distribution at brainly.com/question/16313918

#SPJ1

4 0
1 year ago
What is the factored form of this expression? 27m^3 +125n^3
ddd [48]

Answer:

\left(3m+5n\right)\left(9m^2-15mn+25n^2\right)

Step-by-step explanation:

27m^3+125n^3=\left(3m\right)^3+\left(5n\right)^3

Apply sum of cubes formula: x^3+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)

\left(3m\right)^3+\left(5n\right)^3=\left(3m+5n\right)\left(3^2m^2-3m\times 5n+5^2n^2\right)

\left(3m+5n\right)\left(9m^2-15mn+25n^2\right)

5 0
3 years ago
Read 2 more answers
The area of a circle is 616 m square find the radius 5 equals to 22/7 ​
astra-53 [7]

Step-by-step explanation:

here \: is \: your \: solution :  -  \\  \\ GIVEN  \:  \: -:- \\  \\  =  >  \: area \: of \: circle \:  = 616 \: m {}^{2}  \\  \\ \ =  > pi = 22  \div 7 \\  \\  =  > we \: need \: to \: find \: radius \:  \\  \\  =  > area \: of \: circle \:  = \pi \: r {}^{2}  \\  \\  =  >  \: \pi \: r {}^{2}  = 616 \: m {}^{2}  \\  \\  =  >  \: r {}^{2}  \times (22 \div 7) = 616 \\  \\  =  >  \: r {}^{2}  =( 616 \times 7) \div 22 \\  \\  =  >  \: r {  }^{2}  = 4312 \div 22 \\  \\  =  > r {}^{2}  = 196 \\  \\  =  >  \: r =  \sqrt{196}  \\  \\  =  >  \: r = 14 \: \:   \: (ANSWER✓✓✓) \\  \\ HOPE \:  IT \:  HELPS \:  YOU \: (◕ᴗ◕✿)

7 0
2 years ago
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