All categories

3 years ago

Name the property shown by the statement 2a = a2

Mathematics

1 answer:

valentina_108 [34]3 years ago

7 0

Distributive property

screenshot if you need more words. seems to be a well illustrated and compact explanation right there

You might be interested in

What is the value of x?

Westkost [7]

Answer:

x is equal to 20 in this picture.

Step-by-step explanation:

In order to find this, we need to note that these two angles will be equal to each other. Now we can put their values equal to each other and solve for x.

3x + 50 = 6x - 10

50 = 3x - 10

60 = 3x

20 = x

6 0

3 years ago

Find the absolute extreme of the function on the closed interval. y=9e^xsinx , [0,pi]

Molodets [167]

For convenience sake, I will let $y=f(x)=9e^{x}\sin x$

First, we evaluate the function at the endpoints of the interval.

$f(0)=9e^{0}\sin(0)=0\\\\f(\pi)=9e^{\pi}\sin(\pi)=0$

Then, we need to find the critical points.

We can start by taking the derivative using the power rule.

$f'(x)=9e^{x} \frac{d}{dx} \sin x+9\sin x \frac{d}{dx} e^{x}=9e^{x}(\cos x+\sin x)$

Setting this equal to 0,

$9e^x (\cos x+\sin x)=0$

Since $9e^x > 0$ , we can divide both sides by $9e^x$ .

$\cos x+\sin x=0\\\\\sin x=-\cos x\\\\\tan x=-1\\\\x=\frac{3\pi}{4}$

$f\left(\frac{3\pi}{4} \right)=9e^{3\pi/4}\sin \left(\frac{3\pi}{4} \right)=\frac{9\sqrt{2}e^{3\pi/4}}{2}$

So, the absolute minimum is $\boxed{\left(\frac{3\pi}{4}, \frac{9\sqrt{2}e^{3\pi/4}}{\sqrt{2}} \right)}$ and the absolute minima are $\boxed{(0,0), (\pi, 0)}$

3 0

2 years ago

a survey of 12,089 men in a particular country found that46.1% received a flu vacvine for a recent flu season identify the popul

11Alexandr11 [23.1K]

The population is all men in this particular country.

The sample is the 12,089 men in this particular country that conduct the survey.

5 0

3 years ago

A 3-column table with 3 rows. Column 1 is labeled Number of Tests with entries 2, 1, 2. Column 2 is labeled Score Earned with en

scoray [572]

Answer:

Step-by-step explanation:

Did the assignment :D

8 0

3 years ago

Read 2 more answers

Drag and drop the numbers 1 - 9 into the empty

kakasveta [241]

Answer:

9 for the hypotenuse, $\sqrt{64}$ and $\sqrt{25}$ for the two legs

Step-by-step explanation:

For these types of problems, we need to make sure that the values of legs are as big as possible while keeping the hypotenuse larger than legs because otherwise, it won’t be a right triangle.

So for the hypotenuse, we have to put the largest number in this number bank because the hypotenuse has to be larger than both legs. So the hypotenuse will equal 9. The rest is simple. Get the numbers as large as possible. Since the hypotenuse must be larger than both legs, we cannot use sqrt(81) and sqrt(64) (that would’ve been sweet). So we have to use sqrt(64) and sqrt(25) because sqrt(49) and sqrt(36) are already taken since we can only use a number once.

I'm not an expert at this and I cannot guarentee that this is correct. But I hope that this helps.

4 0

3 years ago