K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also

and

and
![x^ \frac{m}{n}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
and

and

and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)
so

=

=

=

=


=

=
Answer: 
Step-by-step explanation:
Given
Length of Prism is 
The width of Prism is 
The height of Prism is 
The volume of a The height rectangular prism is given as

Substituting values we get

Volume of storage 
The difference in volume is

Answer:
New height = 6
Step-by-step explanation:
The water is going to be the same volume no matter how the tank is orientated.
So you can do this 2 ways.
First way
Find the volume in the tank when the water goes up 24 cm on the height.
V = L*W*h
L = 8
W = 10
H = 24
V = 1920 cm^3
Now do it using the
L = 40
W = 8
h = ?
1920 = L * W * h
1920 = 40 * 8 * h
1920 = 320 * h
h * 320 = 1920
h = 1920/320
h = 6
Or you can do it without finding the 1920
L*W*h = L1 * w1 * h1
8*10*24 = 40 * 8 * h The 8's cancel
10*24 = 40*h Divide both sides by 10
24 = 4h Divide by 4
h = 6
Same as you got before.
Answer:
c=3
Step-by-step explanation: