Answer:
(a) [8, 14]
(b) 
(c)See attachment
Step-by-step explanation:
We want to choose a value of x within 3 units of 11.
(a)Now, 11-3=8 and 11+3=14
The possible values of x ranges is in the closed interval [8,14]
(b) Since x is within 3 units of 11., we have:

Solving the absolute inequality

(c)To draw the number line, we use a closed dot since we have the less than or equal to sign.
I think its letter D because x + 2y fits with the equation and there for -3
It would be a linear function
Answer: 10/14
Step-by-step explanation: