Answer:
38.5 N/C
Explanation:
The electric field generated by a charged sphere at a point outside the sphere is equivalent to the electric field generated by a single point charge, and it is given by
where
is the Coulomb's constant
Q is the net charge
r is the distance from the centre of the sphere
In this problem, we have
Substituting into the equation, we find
1) 29.5 N/m
2) 0.100 m
Explanation:
1)
The force constant of the spring can be found by using the fact that the force on the spring is proportional to the extension of the spring (Hooke's Law). Therefore, we can write:
where
is the change in the force on the spring, where
is the force applied when the hanging mass is
is the force applied when the hanging mass is
is the change in extension of the spring, where
is the extension of the spring when the hanging mass is 0.300 kg
is the extension of the spring when the hanging mass is 1.95 kg
Solving for k,
2)
When the first mass is hanging on the spring, we have
where:
is the force applied on the spring (the weight of the hanging mass)
k is the spring constant
is the extension of the spring wrt its natural length
is the natural length of the spring (the unloaded length)
Here we have
k = 29.5 N/m
Solving for , we find: