The stretching force acting on the second wire, given the data is 588 N
<h3>Data obtained from the question</h3>
- Radius of fist wire (r₁) = 3.9×10⁻³ m
- Force of first wire (F₁) = 450 N
- Radius of second wire (r₂) = 5.1×10⁻³ m
- Force of second wire (F₂) =?
<h3>How to determine the force of the second wire</h3>
F₁ / r₁ = F₂ / r₂
450 / 3.9×10⁻³ = F₂ / 5.1×10⁻³
cross multiply
3.9×10⁻³ × F₂ = 450 × 5.1×10⁻³
Divide both side by 3.9×10⁻³
F₂ = (450 × 5.1×10⁻³) / 3.9×10⁻³
F₂ = 588 N
Learn more about spring constant:
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Because there's no such thing as "really" moving.
ALL motion is always relative to something.
Here's an example:
You're sitting in a comfy cushy seat, reading a book and listening
to your .mp3 player, and you're getting drowsy. It's so warm and
comfortable, your eyes are getting so heavy, finally the book slips
out of your hand, falls into your lap, and you are fast asleep.
-- Relative to you, the book is not moving at all.
-- Relative to the seat, you are not moving at all.
-- Relative to the wall and the window, the seat is not moving at all.
-- But your seat is in a passenger airliner. Relative to people on the
ground, you are moving past them at almost 500 miles per hour !
-- Relative to the center of the Earth, the people on the ground are moving
in a circle at more than 700 miles per hour.
-- Relative to the center of the Sun, the Earth and everything on it are moving
in a circle at about 66,700 miles per hour !
How fast are they REALLY moving ?
There's no such thing.
It all depends on what reference you're using.
Answer:
cola forms so slowly that we could use up the supply that exists now
Answer:
Acceleration due to gravity will be 
Explanation:
We have given gauge pressure P = 3.8 atm = 3.8×101325 = 385035 Pa
Depth h = 24.3 m
Density 
We have find the acceleration due to gravity at the surface of planet
We know that pressure is given by
So 
Acceleration due to gravity will be
B: <span>It contains all of the wavelengths of the visible light spectrum.
Hope this helps mate =)</span>
