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3 years ago

A school principal is mapping out some new features for a triangular playground,

Mathematics

1 answer:

Phoenix [80]3 years ago

3 0

Answer:

(1 ,3.75)

Step-by-step explanation:

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What are some solutions of the question 3x^2-5x+2=0?

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

3x²-5x+2=0

3x²-3x-2x+2=0

3x(x-1)-2(x-1)=0

(x-1)(3x-2)=0

either x-1=0 which gives x=1

or 3x-2=0

x=2/3

7 0

3 years ago

Function 1 is defined by the following table

AnnyKZ [126]

Wjats the best way for you yetwywtw you get your help for your work and work on the building your new job and you can do more homework and your help with the help for help with the family room and your family member and family members are coming now

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2 years ago

For problem 5, use the ordered pairs to answer the following question. MUST SHOW YOUR WORK FOR FINDING SLOPE.

Firlakuza [10]

Answer:

graph them and then see if they intersect(but if you notice that the coordss of the second line are all smaller than the coords of the first line, meaning that they wont be touching at all)

Step-by-step explanation:

7 0

3 years ago

Point O is the center of the circle. What is the value of X? <br> Answer options: 24, 15, 27, 20

Tanya [424]

Answer: FIRST OPTION

Step-by-step explanation:

To solve this problem you must apply the Intersecting Secant-Tangent Theorem. By definition, when a secant line and a tangent lline and a secant segment are drawn to a circle from an exterior point:

$(Tangent\ line)^2=(Secant\ line)(External\ Secant\ line)$

The total measure of the secant shown is:

$18+Diameter$

If the radius is 7, then the diameter is:

$D=7*2=14$

Therefore:

$Secant\ line=18+14=32$

You also know that:

$External\ Secant\ line=18\\Tangent\ line=x$

Keeping the above on mind, you can substitute values and solve for x:

$x^{2}=32*18$

$x=\sqrt{576}\\x=24$

4 0

3 years ago

I still don’t understand can someone give a helping hand?

Fofino [41]

Answer:

Step-by-step explanation:

A, B, C, and D, are all functions. the " { " is saying that those functions can are different at different points. For A the function is $A= -x-2$ when $x< 2$ and then $A=x+4$ when $x\geq -2$ . At the point $x=-2$ you can see that the function on the graph is going in two different directions but it stops at $x=-2$ .

Based on the graph you can see that the line on the left has a slope of -1 and if it kept going it would cross the y-axis at $y=-2$ , therefore the equation for the first line is $y =-x-2$ when $x$

The second line on the right side has a slope of 1 and crosses the y-axis at $y=4$ so the equation for that line is $y=x+4$ when $x\geq -2$ .

The only answer that matches these requirements is A

6 0

3 years ago