A. $1250; $1500 because if you bought something for $1250 and sold it for $1500 you would be gaining $250
Answer:
this might help better
Step-by-step explanation:
5√24
=10√6(Decimal: 24.494897)
Answer:
(2x+5)
Step-by-step explanation:
2x^2 + 7x + 5 = (x + 1) (?)
Must multiply to 10 and add to 7:
5 and 2
(2x^2+2x)(5x+5)
2x(x+1)5(x+1)
(2x+5)(x+1)
Hope this helps! Please mark brainliest :)
Answer:
9 times
Step-by-step explanation:
Area = length x breadth
area of picture not enlarged = 3 x 5 = 15in²
If length is tripled it becomes , 3 x 3 = 9in
If width is tripled, it becomes , 5 x 3 = 15in
Area of enlarged picture = 9in x 15in = 135in²
amount by which enlarged image is larger = 135in² /15in² = 9
Answer:
a) Z= 0.0228
b) based on the critical value, it is a one tailed test
c) Since the p-value is less than the level of significance (α= 0.05) so we reject the null hypothesis.
This implies that the advertising campaign has been effective in increasing sales.
Step-by-step explanation:
The null hypothesis is H₀ : µ = 8000
The alternative hypothesis is H₁ : µ ˃ 8000
Mean (µ) = 8000
Standard deviation (σ) = 1200
n = 64
We will use the Z test to test the hypothesis
Z = (X - µ)/ (σ/√n)
Z = (8300 – 8000)/ (1200/√64)
Z = 300/ (1200/8)
Z = 300/ 150
Z= 2
From the normal distribution table,
2 = 0.4772
Φ(z) = 0.4772
Since Z is positive,
P(x˃a) =0.5 - Φ(z)
= 0.5 – 0.4773
= 0.0228
The required P-value = 0.0228
The P-value of one tail Z test at α= 0.05 level of significance
P-value = p(Z˃2.5)
= 0.0228
Since the p-value is less than the level of significance (α= 0.05) so we reject the null hypothesis.
This implies that the advertising campaign has been effective in increasing sales.
