Question

Find the value x ? (2x -10degree) (3x +20degree)​

Answer 1

Answer:

If we do square on both sides we get two answers i.e. (x+12)^2=(3x+20)^2

(x^2)+24x+144=(9x^2)+120x+400

(8x^2)+96x+256=0

(x^2)+12x+32=0

(x+4)(x+8)=0

x= -4 or x= -8.

Else we have another method

x+12=3x+20

x+12–20=3x

x-8=3x,

Now square on both sides.

(x-8)^2=(3x)^2

x^2–16x+64=(9x^2)

(9x^2)-(x^2)+16x-64=0

(8x^2)+16x-64=0

(x^2)+2x-8=0

(x+4)(x-2)=0

x= -4 or x= 2.

But It Didn’t Satisfy for The Equation When

x=2 or x= -8,So The Value of x will be -4 which satisfies given question.