Answer:
x = 1
y = 3
Step-by-step explanation:
<h2>
<em><u>Substitution Method</u></em><em><u>:</u></em></h2>
Step 1:
Name The Equation
4x + y = 7 ...(1)
3x + 2y = 9 ...(2)
Step 2:
From Equation (1) we get,
4x = 7 - y
i.e.,
x = 7 - y/4
Step 3:
Substitute the value of <em><u>x = 7 - y/4</u></em> in equation (2)
i.e.,
3(7 - y/4) + 2y = 9
21 - 3y/4 + 2y = 9
21 - 3y + 8y/4 = 9
21 - 3y + 8y = 9 * 4
21 + 5y = 36
5y = 36 - 21
5y = 15
y = 15/5
<em><u>y = 3</u></em>
Step 4:
Substitute the value of <em><u>y = 3</u></em> in equation (1)
4x + y = 7
i.e.,
4x + (3) = 7
4x + 3 = 7
4x = 7 - 4
4x = 4
x = 4/4
<em><u>x = 1</u></em>
<h2><em><u>Verification</u></em><em><u>:</u></em><em><u> </u></em></h2>
4x + y = 7 i.e., <em>4(1) + (3) = 7</em>
3x + 2y = 9 i.e., <em><u>3(1) + 2(3) = 9</u></em>
(t + 8) (-2) = 12
Distributive property >>> -2t + -16 = 12
Inverse operation >>>> -2t + -16+16 = 12+16
Simplify >>>> -2t = 28
Divide >>>> -2t/-2 = 28/-2
Final answer >>>> t = -14
Answer:
Step-by-step explanation:
Since the number of pages that this new toner can print is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the number of pages.
µ = mean
σ = standard deviation
From the information given,
µ = 2300 pages
σ = 150 pages
1)
the probability that this toner can print more than 2100 pages is expressed as
P(x > 2100) = 1 - P(x ≤ 2100)
For x = 2100,
z = (2100 - 2300)/150 = - 1.33
Looking at the normal distribution table, the probability corresponding to the z score is 0.092
P(x > 2100) = 1 - 0.092 = 0.908
2) P(x < 2200)
z = (x - µ)/σ/√n
n = 10
z = (2200 - 2300)/150/√10
z = - 100/47.43 = - 2.12
Looking at the normal distribution table, the probability corresponding to the z score is 0.017
P(x < 2200) = 0.017
3) for underperforming toners, the z score corresponding to the probability value of 3%(0.03) is
- 1.88
Therefore,
- 1.88 = (x - 2300)/150
150 × - 1.88 = x - 2300
- 288 = x - 2300
x = - 288 + 2300
x = 2018
The threshold should be
x < 2018 pages
First of all, let's take a look on the question.
![\large{15 + 0 = 15}](https://tex.z-dn.net/?f=%5Clarge%7B15%20%2B%200%20%3D%2015%7D)
Here, 0 is added to 15 and the resultant is 15 only. So, we can say that 0 when added with any number gives the same number as the resultant.
So, the property is known as <u>Identi</u><u>ty</u> property because 0 is added to get the identity of the same number.
<u>The Correct Option:</u>
![\large{ \boxed{ \red{ \bf{Option \: C}}}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Cboxed%7B%20%5Cred%7B%20%5Cbf%7BOption%20%5C%3A%20C%7D%7D%7D%7D)
So, let's know more...
- Commutative property ➝ a + b = b + a
- Associative property ➝ a + (b + c) = (a + b) + c
- Distributive property ➝ a(b + c) = ab + ac
So this is the general form of these properties which is general observed in the rational numbers.
<u>━━━━━━━━━━━━━━━━━━━━</u>
Answer: It will take 6 years for 7500 grams of X to reach 6900 grams.
Step-by-step explanation:
Expression for rate law for first order kinetics is given by:
![t=\frac{2.303}{k}\log\frac{a}{a-x}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7Ba%7D%7Ba-x%7D)
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
![51=\frac{0.69}{k}](https://tex.z-dn.net/?f=51%3D%5Cfrac%7B0.69%7D%7Bk%7D)
![k=\frac{0.69}{51}=0.0135years^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B0.69%7D%7B51%7D%3D0.0135years%5E%7B-1%7D)
b) for 7500 g to reach to 6900 g
![t=\frac{2.303}{0.0135}\log\frac{7500}{6900}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7B0.0135%7D%5Clog%5Cfrac%7B7500%7D%7B6900%7D)
![t=6years](https://tex.z-dn.net/?f=t%3D6years)
It will take 6 years for 7500 grams of X to reach 6900 grams.