What are the domain and range of the function f(x)=square root x-7 +9?
2 answers:
Answer:
Domain is all real numbers greater than or equal to 7. Range is all real numbers greater than or equal to 9.
Step-by-step explanation:
The domain is possible x-values while the range is possible y-values. This question look like
The domain of square root function cant have a the radical inside being a negative number because we can't take the sqr root of a negative number and graph it on a cartisean plane We can take the sqr root of 0 . So we set x-7=0. And which x=7 so the domain is all real numbers that are equal to or greater than 7. The range of a sqr root function can only yield any positive y-values. So we must find the lowest point of it. Since the lowest x value we can possible use is 7 we plug it in
which equals 9. So the range is all real numbers greater than or equal to 9.
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Answer:
Distance between the points A and B is 15.52 units.
Step-by-step explanation:
It has been given in the question that an airplane flies along a straight line from City A to City B.
Map has been laid out in the (x, y) coordinate plane and the coordinates of these cities are A(20, 14) and B(5, 10).
Distance between two points A'(x, y) and B'(x', y') is represented by the formula,
d =
So we plug in the values of (x, y) and (x', y') in the formula,
d =
d =
d =
d = 15.52
Therefore, distance between the points A and B is 15.52 units.