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Tamiku [17]
3 years ago
8

What are the domain and range of the function f(x)=square root x-7 +9?

Mathematics
2 answers:
MArishka [77]3 years ago
8 0

Answer:

Domain is all real numbers greater than or equal to 7. Range is all real numbers greater than or equal to 9.

Step-by-step explanation:

The domain is possible x-values while the range is possible y-values. This question look like

\sqrt{x - 7}   + 9

The domain of square root function cant have a the radical inside being a negative number because we can't take the sqr root of a negative number and graph it on a cartisean plane We can take the sqr root of 0 . So we set x-7=0. And which x=7 so the domain is all real numbers that are equal to or greater than 7. The range of a sqr root function can only yield any positive y-values. So we must find the lowest point of it. Since the lowest x value we can possible use is 7 we plug it in

\sqrt{7- 7}  + 9

which equals 9. So the range is all real numbers greater than or equal to 9.

amid [387]3 years ago
4 0

Answer:

<em>I think that the short answer will be C) on edge.</em>

Step-by-step explanation:

<em>Edge 2021.</em>

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