Question

What are the domain and range of the function f(x)=square root x-7 +9?

Answer 1

Answer:

Domain is all real numbers greater than or equal to 7. Range is all real numbers greater than or equal to 9.

Step-by-step explanation:

The domain is possible x-values while the range is possible y-values. This question look like

$\sqrt{x - 7} + 9$

The domain of square root function cant have a the radical inside being a negative number because we can't take the sqr root of a negative number and graph it on a cartisean plane We can take the sqr root of 0 . So we set x-7=0. And which x=7 so the domain is all real numbers that are equal to or greater than 7. The range of a sqr root function can only yield any positive y-values. So we must find the lowest point of it. Since the lowest x value we can possible use is 7 we plug it in

$\sqrt{7- 7} + 9$

which equals 9. So the range is all real numbers greater than or equal to 9.

Answer 2

Answer:

I think that the short answer will be C) on edge.

Step-by-step explanation:

Edge 2021.