Convex Polygons

All of its angles are less than 180°.
All of the diagonals are internal.
Concave Polygons

At least one angle measures more than 180°.
At least one of the diagonals is outside the shape of the polygon.
Equilateral Polygons

All sides are equal.
Equiangular Polygons

All angles are equal.
Regular Polygons

They have equal angles and sides
Irregular Polygons
They do not have equal angles and sides.
Types of Polygons based on Number of Sides
Triangle

3 sides.
Quadrilateral

4 sides.
Pentagon

5 sides.
Hexagon

6 sides.
Heptagon

7 sides.
Octagon

8 sides.
Enneagon or Nonagon

9 sides.
Decagon

10 sides.
Hendecagon

11 sides.
Dodecagon

12 sides.
Tridecagon or triskaidecagon

13 sides.
Tetradecagon or tetrakaidecago

14 sides.
Pendedecagon

15 sides.
Hexdecagon

16 sides.
Heptdecagon

17 sides.
Octdecagon

18 sides.
Enneadecagon

19 sides.
Icosagon

20 sides.
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
Answer:
second option
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
∠ 1 and 33° form a straight angle and are supplementary, thus
∠ 1 = 180° - 33° = 147°
----------------------------------
The third angle in the triangle on the left is
180° - (33 + 47)° = 180° - 80° = 100°, thus
∠ 2 = 180° - 100° = 80°
--------------------------------------
∠ 2 and the angle in the triangle form a straight angle and are supplementary,
angle = 180° - 80° = 100°
The third angle in the triangle on the right is
180° - (100 + 48)° = 180° - 148° = 32°, thus
∠ 3 = 180° - 32° = 148° ( straight angle )
Thus
∠ 1 = 147°, ∠ 2 = 80°, ∠ 3 = 148°
3x-5y=25 i hope this helps
