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2 years ago

HELP PLZS FAST BRAINIEST

Mathematics

2 answers:

kirill115 [55]2 years ago

3 0

Answer:

x=-2, y=-2. (-2, -2).

Step-by-step explanation:

2x-5y=6

-2x+10y=-16

-------------------

5y=-10

y=-10/5=-2

2x-5(-2)=6

2x+10=6

2x=6-10

2x=-4

x=-4/2=-2

amid [387]2 years ago

3 0

Step-by-step explanation:

#hehdehwhshshhsheejebbxjjsjf

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Was this answer helpful

8 0

2 years ago

BRAINY

likoan [24]

Answer:

correct answer is four sixths

Step-by-step explanation:

you can simplify 2/6 to 1/3 and then it would just be 1/3 plus 1/3. This is 2/3 or 4/6! Hope this helps :)

5 0

2 years ago

GOOD MORNING! ＼(:0:)／

Elza [17]

Answer:

Good morning.

Step-by-step explanation:

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8 0

2 years ago

Read 2 more answers

After 15% discount an item cost $22.27 what was the original price?

musickatia [10]

Orig - .15 * orig = 22.27
.85 * orig = 22.27
Original price = 26.20

6 0

3 years ago

Read 2 more answers

Thirty percent of all customers who enter a department store will make a purchase. Suppose that 6 customers enter the store and

torisob [31]

Answer:

Step-by-step explanation:

Let's use binomial distribution, because we are interested in find the total number of successes in a sequence of n independent experiments.

In probability, a binomial distribution is used in a Bernoulli process. That is, a sequence of experiments of n independent trials, each asking a dichotomous question, that means it only has two answers. One answer is a success (probability: p) and the other is a failure (probability: 1-p). In this case, every customer who enters in the store is the experiment. If they make a purchase is a success event, taking into account that every purchase decision has to be independent.

$P(X=x) = C(n,x)p^{x} (1-p)^{n-x}$

x= total number of success

n= total number of experiments

p=probability of success on an indivual trial

$C(n,x) = \frac{n!}{x!(n-x)!}$

a) x= 5 ------> customers that make a purchase

n= 6 ------> total customers

p=0.3

$p(X=5)= C(6,5)(0.3)^{5} (1-0.3)^{6-5} \\p(X=5)=0.102$

b) At least 3 customers make a purchase. x ≥ 3

$P(X\geq 3)=1-P (X=0)-P(X=1)-P(X=2)\\P(X\geq 3)=1-(C(6,0)(0.3^{0})(0.7)^{6}) - (C(6,1)(0.3^{1})(0.7)^{5}) - (C(6,2)(0.3^{2})(0.7)^{4})\\ P(X\geq 3) = 1-0.11765-0.30253-0.32414\\P(X\geq3)= 0.2557$

c) At most 2 customers make a purchase. x ≤ 2

$P(X\leq2) = P(X=0) + P(X=1) + P(X=2)\\P(X\leq2) = (C(6,0)(0.3^{0})(0.7)^{6}) + (C(6,1)(0.3^{1})(0.7)^{5}) + (C(6,2)(0.3^{2})(0.7)^{4})\\P(X\leq2) = 0.11765-0.30253-0.32414\\P(X\leq2)=0.7443$

d)At least 1 customer makes a purchase. x ≥ 1

$P(X\geq 1)=1-P(X=0)\\P(X\geq 1)= 1-C(0,6)(0.3)^{0}(0.7)^{6} \\P(X\geq 1)= 1-0.11765 = 0.8824$

e)They must be kind to customers, always willing to help and give information about products clearly and honestly.

Have enough inventory and offer promotions for the purchase of more than one product

Have an agile payment system that avoids rows and delays in purchases.

6 0

3 years ago