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Mademuasel [1]
3 years ago
8

What are some other molecules in the plasma membrane explain their function.

Chemistry
2 answers:
chubhunter [2.5K]3 years ago
8 0
Answer: Lipids, phospholipids, cholesterol, proteins, carbohydrates.

Function of a lipid is storing energy signaling and acting as cell membranes.

Function of a protein is that it helps build and repair yours body’s tissues

Function of cholesterol is that it serves as a precursor for the synthesis of substances like hormones, bile acids, and vitamin D

Function of carbohydrates is that it provides you with energy and it’s a fuel source for your brain.


Explanation: Have a good rest of your day!
Cerrena [4.2K]3 years ago
5 0

Answer:..

Explanation:

You might be interested in
Need help ASAP!!!! what is the value (angle) for the C=C=O bond in Ketene i.e. CH2=C=O
stepan [7]

Answer:

180^\circ by the VSEPR theory.

Explanation:

This question is asking for the bond angle of the \rm C=C=O bond in \rm H_2C=C=O. The VSEPR (valence shell electron pair repulsion) theory could help. Start by considering: how many electron domains are there on the carbon atom between these two bond?

Note that "electron domains" refer to covalent bonds and lone pairs collectively.

  • Each nonbonding pair (lone pair) of valence electrons counts as one electron domain.
  • Each covalent bond (single bond, double bond, or triple bond) counts as exactly one electron domain.

For example, in \rm H_2C=C=O, the carbon atom at the center of that \rm C=C=O bond has two electron domains:

  • This carbon atom has two double bonds: one \rm C=C bond and one \rm C=O bond. Even though these are both double bonds, in VSEPR theory, each of them count only as one electron domain.
  • Keep in mind that there are only four valence electrons in each carbon atom. It can be shown that all four valence electrons of this carbon atom are involved in bonding (two in each of the two double bonds.) Hence, there would be no nonbonding pair around this atom.

In VSEPR theory, electron domains around an atom repel each other. As a result, they would spread out (in three dimensions) as far away from each other as possible. When there are only two electron domains around an atom, the two electron domains would form a straight line- with one domain on each side of the central atom. (To visualize, consider the three atoms in this \rm C=C=O bond as three spheres on a stick. The central \rm C atom would be between the other \rm C atom and the \rm O atom.)

This linear geometry corresponds to a bond angle of 180^\circ.

3 0
3 years ago
Ann drove to the store km north of her house and then drove to the library, which is 5 km south of the store. She drove a total
Vadim26 [7]
Answer : The question is incomplete, the complete question is attached in answer

To calculate the displacement by Ann's driving from north of her house to south;

we have the data as 

In north - 10 km
in south - 5 km
total - 15 km

So we can calculate the displacement, which will be,

10 - 5 = 5 km.

Hence, the displacement will be 5 km 


3 0
3 years ago
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is t
Artist 52 [7]

Answer:

pKa = 3.51

Explanation:

The titration of acid solution with NaOH can be illustrated as:

AH + NaOH \to NaA + H_2O

Given that:

Volume of acid solution (V_1) = 25 \ mL

Volume of NaOH (V_2) = 18.8 \ mL

Molarity of acid solution (M_1) = ???

Molarity of NaOH (M_2) = 0.10 \ M

For Neutralization reaction:

M_1V_1 = M_2V_2

Making M_1 the subject of the formula; we have:

M_1 = \frac{M_2V_2}{V_1}

M_1 = \frac{0.10*18.8}{25}

M_1 =0.0752 \ M  

However; since the number of moles of NaA formed is equal to the number of moles of NaOH used : Then :

M_2V_2 = 0.10 *18.8 = 1.88 \ mm

Total Volume after titration = ( 25 + 18.8 ) m

= 43.8 mL

Molarity of salt (NaA ) solution = \frac{number \ of \ moles}{Volume \  (mL)}

= \frac{1.88}{43.8}

= 0.0429 M

After mixing the two solution ; the volume of half neutralize solution is = 25 mL + 43.8 mL

= 68.8 mL

Molarity of NaA before mixing M_1 = 0.0429 \ M

Volume (V_1) = 43.8 \ mL

Molarity of NaA after mixing M_2 = ???

Volume (V_2 ) = 68.8 \ mL

∴

M_2 = \frac{M_1*V_1}{V_2} \\ \\ M_2 = \frac{0.0429*43.1}{68.8} \\ \\ M_2 = 0.0273 \ M

Molarity of acid before mixing = 0.0725 M

Volume = 25 mL

Molarity of acid after mixing = \frac{0.0752*25}{68.8}

= 0.0273 M

Since this is a buffer solution ; then using Henderson Hasselbalch Equation

pH = pKa + log \frac{[salt]}{[acid]}

3.51= pKa + log \frac{[0.0273]}{[0.0273]} \\  \\ 3.51= pKa + log \ 1  \\ \\ 3.51= pKa + 0 \\ \\ pKa = 3.51

4 0
4 years ago
Explain why sodium (metal) is soft and can be bend, whereas NaCl is hard and brittle.
julia-pushkina [17]

Answer:

Sodium chloride has a crystalline face-centered  cubic structure whereas metallic sodium body-centered  cubic structure.

Explanation:

Hello, atomic arrangements provide the molecules different features and behaviors, since the sodium metal has a body-centered cubic structure (https://en.wikipedia.org/wiki/Cubic_crystal_system#/media/File:Cubic-body-centered.svg) the lack of inner atoms, allows the material to be soft and bendable. On the other hand the compacted sodium chloride's face-centered  cubic structure (https://en.wikipedia.org/wiki/Cubic_crystal_system#/media/File:Cubic-face-centered.svg), provides it a crystalline structure which is hard and brittle since the atoms are closer.

Best regards!

7 0
3 years ago
Any 4 characteristics of catalyst​
Ivan

Answer:

Any 4 characteristic of catalyst are:

1. Catalysts remain unchanged at the end of chemical reaction in their mass and structure.

2. They donot start the chemical reaction.

3. They change the rate of the chemical reaction.

4. Catalyst is specific to the chemical reaction. It means that one catalyst can alter the rate of only one chemical reaction.

8 0
3 years ago
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