All categories

3 years ago

Question in picture plsss help

Chemistry

1 answer:

oksano4ka [1.4K]3 years ago

8 0

Answer:

2nd answer is correct. Hope it helped you!

You might be interested in

Is this a model of an element, a compound, or a mixture? Explain your reasoning.

grandymaker [24]

Answer:

A mixture

Explanation:

Yes

6 0

4 years ago

7. An element's most stable ion forms an ionic compound with chlorine having the formula XCl2. If the ion of element X has a mas

Serhud [2]

Answer:

The element is strontium and the number of neutrons it have is 51.

Explanation:

Based on the given information, the ionic compound is,

XCl₂ ⇔ X₂⁺ + 2Cl⁻

X2+ is the ion of the mentioned element

As mentioned in the given question, the number of electrons of the element X is 36 and as seen from the reaction the charge present on the ion is +2. Now the atomic number will be,

No. of electrons = atomic number - charge

36 = atomic number - 2

Atomic number = 38

Based on the periodic table, the atomic number 38 is for strontium element, and the sign of strontium is Sr. Hence, the element X is Sr.

Now based on the given information, the mass number of the element is 89. Now the no. of neutrons will be,

No. of neutrons = mass number - atomic number

= 89 - 38

= 51 neutrons.

4 0

3 years ago

What is the element of H₂O

slega [8]

Answer:

It’s water bro

Explanation:

6 0

3 years ago

Help me with this question?!!

olya-2409 [2.1K]

Answer:

500 mL

Explanation:

Step 1: Find conversions

1 mL = 0.0338 oz

Step 2: Use Dimensional Analysis

$16.9 \hspace{2} oz(\frac{1 \hspace{2} mL}{0.0338 \hspace{2} oz} )$ = 500 mL

3 0

3 years ago

Indicate what happens to the concentration of Pb2+ in each half cell

Taya2010 [7]

Answer:

Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below

The correct answer is (d) the left half-cell will decrease in concentration; and the right half-cell will increase in concentration.

Explanation:

The concentration of the Pb2+ increases in the oxidation half cell while the concentration of the Pb2+ decreases in the reduction half cell during the reaction.

In the Left Beaker (Left half cell), their is less concentration

Pb(s) ---> Pb2+(aq) + 2 e- Concentration of Pb2+(aq) increase ; Electrons going out from this side

In the Right Beaker (right half cell), their is more concentration

Pb2+(aq) + 2 e- ---> Pb(s) Concentration of Pb2+(aq) decrease ; Electrons coming in to this side

Electrons will flow from Left to Right direction.

3 0

3 years ago