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erica [24]
3 years ago
6

7) Explain how tsunamis are formed. How do tsunamis change the surface of the Earth?

Chemistry
1 answer:
Virty [35]3 years ago
5 0
Well, for starters:

Tsunamis are formed by tectonic plates smashing into one another. 
They are caused by earthquakes, landslides, volcanic eruptions, and even under sea earth quakes.

Hope this helps!
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The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Delicious77 [7]

<u>Answer:</u>

<u>For a:</u> The edge length of the crystal is 533.5 pm

<u>For b:</u> The atomic radius of potassium is 231.01 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the lattice parameter or edge length of the crystal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 0.855g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal = 39.09 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = ?

Putting values in above equation, we get:

0.855=\frac{2\times 39.09}{6.022\times 10^{23}\times (a)^3}\\\\\a=5.335\times 10^{-8}cm=533.5pm

<u>Conversion factor:</u>  1cm=10^{10}pm

Hence, the edge length of the crystal is 533.5 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 533.5 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 533.5}{4}=231.01pm

Hence, the atomic radius of potassium is 231.01 pm

4 0
3 years ago
Unlike carbohydrates and lipids proteins contain which element?
Harman [31]

Answer:

The answer to your question is: Nitrogen

Explanation:

Organic molecules that are part of living organisms are composed by

Carbon, Hydrogen, Oxygen, Nitrogen, Phosphorus and Sulphur.

The elements available in more quantity are Carbon, Hydrogen and Oxygen.

Nitrogen is present in proteins and nucleic acids.

4 0
3 years ago
What does vascular mean
-BARSIC- [3]
<span>of, relating to, affecting, or consisting of a vessel or vessels, especially those that carry blood</span>
5 0
3 years ago
.
Assoli18 [71]
The answer should be d but it could be c
4 0
3 years ago
Read 2 more answers
Hydrogen-3 has a half-life of 12.3 years. How long will it take a sample of 88 g of hydrogen-3 to decay to 11 g? Give your answe
Georgia [21]

The time taken for Hydrogen-3 to decay from 88 g to 11 g is 36.9 years.

<h3>Half-life:</h3>

This can be defined as the time taken for half the sample of a substance to decay or disintegrate

To calculate the time it will take Hydrogen to decay from 88g to 11 g we use the formula below.

Formula:

  • R = R'(2^{T/n})................ Equation 1

Where:

  • R = Original sample of Hydrogen
  • R' = Sample of Hydrogen left after decay
  • T = Total time of decay
  • n = Half-life of hydrogen.

From the question,

Given:

  • R = 88 g
  • R' = 11 g
  • n = 12.3 years.

Substitute these values into equation 1

  • 88 = 11(2^{T/12.3})

Solve for T.

  • 2^{T/12.3} = 88/11
  • 2^{T/12.3} = 8
  • 2^{T/12.3} = 2³................ Equation 2

Equating the base in equation 2 above,

  • T/12.3 = 3
  • T = 12.3×3
  • T =  36.9 years.

Hence, the time taken for Hydrogen-3 to decay from 88 g to 11 g is 36.9 years

Learn more about half-life here: brainly.com/question/11152793

6 0
3 years ago
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