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nadezda [96]
3 years ago
15

Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life

periods
Chemistry
1 answer:
skelet666 [1.2K]3 years ago
3 0

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

\tt 3\times 12.4=37.2~hours

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One molecule of sucrose is burned with oxygen to make carbon dioxide and water.

Disaccharide sugar sucrose is composed of glucose and fructose. It is produced naturally by plants and is the main component of white sugar. C₁₂H₂₂O₁₁ is the chemical formula for it.

Extraction and refining sucrose for human use can be done from either sugarcane or sugar beet. Raw sugar is created from crushing the cane, which is consistently delivered to other sectors to be refined into pure sucrose. Sugar mills generally are located in the tropical regions near the sugarcane plantations.

<em>                    C₁₂H₂₂O₁₁ + 12O₂  →  12CO₂ + 11H₂O</em>

When one molecule of sucrose is burnt, we get 12 carbon dioxide molecules.

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brainly.com/question/978083

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