Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
Answer:
In C++:
#include <cstdlib>
#include <ctime>
#include <iostream>
#include <bits/stdc++.h>
using namespace std;
void printarray(int array []){
for(int i=0; i<100; i++){ cout << array[i] << " "; }
}
void sortarray(int array []){
sort(array, array + 100);
printarray(array);
}
int main() {
int array[100];
srand((unsigned)time(0));
for(int i=0; i<100; i++){ array[i] = (rand()%99); }
printarray(array);
cout<<endl;
sortarray(array);
return 0;
}
Explanation:
<em>See attachment for program source file where comments are used for explanation purpose</em>
Answer:
I think we are so this is hard lol
Explanation:
we are not too dependable
things that show this is library are still open, school sports teams still flourish(if we were too depending on them they wouldnt) they help us plan ways to interact in person if we were too dependent businesses would struggle more and only be online
this is hard if I can think of any others I'll come back I'm sorry if this isn't any help
Answer:
answer is Set of information gathered together
