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Alenkinab [10]
3 years ago
14

A right triangle has legs of length 4x and 20x. What is an expression for the hypotenuse of the right triangle

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

4x\sqrt{26}.

Step-by-step explanation:

Given information:

Leg_1=4x

Leg_2=20x

According to the Pythagoras theorem,

(hypotenuse)^2=(Leg_1)^2+(leg_2)^2

Using Pythagoras theorem, we get

(hypotenuse)^2=(4x)^2+(20x)^2

(hypotenuse)^2=16x^2+400x^2

(hypotenuse)^2=416x^2

Taking square root on both sides.

hypotenuse=\sqrt{416x^2}

hypotenuse=4x\sqrt{26}

Hence, the expression of the hypotenuse is 4x\sqrt{26}.

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Which number line represents the solution set for the inequality –4(x + 3) ≤ –2 – 2x?
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Answer:

–4(x + 3) ≤ –2 – 2x

>>.....-4x -12 ≤ -2 -2x

>>  -12 +2 ≤ +2x  

>> - 10 ≤ 2x

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Step-by-step explanation:

you didn't post any number lines...

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Answer:

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Step-by-step explanation:

Let us see the basic rule to find the orientation of parabolas.

1.  If power if x is 2 and y is 1 , the parabola opens up or down.

2. If the power of y is 2 and that of x is 1 , the parabola opens right or left.

3. If the coefficient of x^{2} in case 1 is negative it opens downward

4. If the coefficient of y^{2}  in case 2 is negative , it opens left towards negative x axis.

Hence our equation is

x=y^2-9

here is satisfies the case 2. hence it opens right or left . Also the coefficient of  

y^{2} is positive so it opens up to the right side , that is towards positive x axis.

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