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Alenkinab [10]
3 years ago
14

A right triangle has legs of length 4x and 20x. What is an expression for the hypotenuse of the right triangle

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

4x\sqrt{26}.

Step-by-step explanation:

Given information:

Leg_1=4x

Leg_2=20x

According to the Pythagoras theorem,

(hypotenuse)^2=(Leg_1)^2+(leg_2)^2

Using Pythagoras theorem, we get

(hypotenuse)^2=(4x)^2+(20x)^2

(hypotenuse)^2=16x^2+400x^2

(hypotenuse)^2=416x^2

Taking square root on both sides.

hypotenuse=\sqrt{416x^2}

hypotenuse=4x\sqrt{26}

Hence, the expression of the hypotenuse is 4x\sqrt{26}.

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alexandr1967 [171]

Answer:

y = \frac{1}{2} x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

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y = - 2x + 2 ← is in slope- intercept form

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The line crosses the y- axis at (0, 1) ⇒ c = 1 , then

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Answer:

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