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Lostsunrise [7]
3 years ago
8

The sides of a triangle are given as 3x, x - 1 and 3x + 1. If the perimeter [2]

Mathematics
2 answers:
wariber [46]3 years ago
5 0

Answer:

The sides of the triangle are:

  • 3x = 3(8)=24
  • x-1=8-1=7
  • 3x+1=3(8)+1=25

Step-by-step explanation:

  • We know that the perimeter of a triangle is the sum of the length of its sides.

As the sides are given

  • 3x
  • x-1
  • 3x+1

so the equation of the perimeter becomes

P=3x+\left(x-1\right)+\left(3x+1\right)\:

as

  • P = 56m

so

56=3x+\left(x-1\right)+\left(3x+1\right)

3x+x+3x-1+1=56

7x-1+1=56

7x=56

\frac{7x}{7}=\frac{56}{7}

x=8

Now finding the sides

3x = 3(8)=24

x-1=8-1=7

3x+1=3(8)+1=25

Therefore, the sides of the triangle are:

  • 3x = 3(8)=24
  • x-1=8-1=7
  • 3x+1=3(8)+1=25
sveta [45]3 years ago
3 0

Answer:

The sides are 24cm, 7cm, and 25cm

Step-by-step explanation:

3x+x-1+3x+1=56 <---- First we combine like terms (the 1's cancel out)

7x/7=56/7 <--- Divide by 7 to isolate the variable

x=8 <--- Now that we've solved for x we need to plug it back into each side

3(8)=24

(8)-1=7

3(8)+1=25

24+25+7=56 <---- Make sure it all adds up to 56

Hope this helps :)

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