f(x)=x3−5
Replace f(x)
with y
.
y=x3−5
Interchange the variables.
x=y3−5
Solve for y
.
Since y
is on the right side of the equation, switch the sides so it is on the left side of the equation.
y3−5=x
Add 5
to both sides of the equation.
y3=5+x
Take the cube root of both sides of the equation to eliminate the exponent on the left side.
y=3√5+x
Solve for y
and replace with f−1(x)
.
Replace the y
with f−1(x)
to show the final answer.
f−1(x)=3√5+x
Set up the composite result function.
f(g(x))
Evaluate f(g(x))
by substituting in the value of g into f
.
(3√5+x)3−5
Simplify each term.
Remove parentheses around 3√5+x
.
f(3√5+x)=3√5+x3−5
Rewrite 3√5+x3
as 5+x
.
f(3√5+x)=5+x−5
Simplify by subtracting numbers.
.
Subtract 5
from 5
.
f(3√5+x)=x+0
Add x
and 0
.
f(3√5+x)=x
Since f(g(x))=x
, f−1(x)=3√5+x is the inverse of f(x)=x3−5
.
f−1(x)=3√5+x
Answer:
Respect Girls!
Don't Post Unwanted things.
I know u r from India.
In Indian Server it is common.
Step-by-step explanation:
Add 44 to both sides.
2x=10+4
2x=10+4
2 Simplify 10+410+4 to 1414.
2x=14
2x=14
3 Divide both sides by 22.
x=\frac{14}{2}
x=
2
14
4 Simplify \frac{14}{2}
2
14
to 77.
x=7
x=7
Done
<u>First what I did was find how much each pound would cost per different package. </u>
<u>So starting off with the 3 pound package. I did 2.49 divided by 3 to find out how much each pound would weigh. </u>
2.49 / 3 = 0 . 83
<u>So each pound in the 3 pounded package would cost $0.83. </u>
<u>Now to see how much the 8 pound package would cost. Just like the 3 pound package I had to find how much each pound would weigh. So I divided 6.49 by 8. </u>
6.49 / 8 = 0.81125
<u>So looking at the results the 3 pound package would be the best option. You are getting more for less. </u>
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HOPES THIS HELPS!
