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3 years ago

5

Cameron won a laptop in a school raffle. The diagonal of the laptop measures 26 inches. The length is 24 inches. How tall is the

computer screen?
plz help me

1 answer:

Over [174]3 years ago

4 0

I need help to with this

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at the start of the shift your part counter reads 250 at the end of the shift the part counter reads 1075 how many parts did you

Luden [163]

This can be mathematically expressed to
250 + X = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825

You produced 825 parts in the middle of the shift.

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3 years ago

Help ASAP I need to get this question correct

strojnjashka [21]

Answer: The answer is NO

Step-by-step explanation:

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3 years ago

Help me please<br> thx so much<br> have a good one

Mademuasel [1]

Answer: y=1/2x-17

Step-by-step explanation:

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3 years ago

Jillian measured how far each of her paper airplanes flew in feet.

Evgesh-ka [11]

Answer:

72

Step-by-step explanation:

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3 years ago

A rancher wishes to build a fence to enclose a rectangular pen having area 24 square yards. Along one side the fence is to be ma

Gnoma [55]

Answer:

The value is $C \approx \$76$

Step-by-step explanation:

From the question we are told that

The area of the rectangular pen is $A = 24 \ yard^2$

The cost of material used to make one side is $z = \$ 6$

The cost of material used to make the other sides is $r = \$ 3$

Now , the fence to be build around the rectangular pen has four sides, the first opposite sides are equal, let assume each of the to be x yard and the other opposite sides are also equal as well let assume of the to be y yard

So the cost is mathematically represented as

$C = zx + r (x + 2y )$

=> $C = 6x + 3(x + 2y)$

=> $C = 9x + 6y$

Now the area of the fence is mathematically represented as

$A = x* y = 24$

=> $y = \frac{24}{x}$

=> $C = 9x + 6[\frac{24}{x} ]$

=> $C = 9x + [\frac{144}{x} ]$

Now differentiating

$C' = 9 + 144* (-2) x^{-2}$

$C' = 9 - 288x^{-2}$

At minimum $C' = 0$

So

$9 - 288x^{-2} = 0$

$x^{-2} = 0.03125$

$x = \sqrt{\frac{1}{0.03125} }$

$x = 5.66$

Now substituting for x in the equation above to obtain minimum cost

$C = 9(5.66) + [\frac{144}{5.66} ]$

$C \approx \$76$

8 0

3 years ago