What is the smallest of three consecutive positive integers if the product of the smaller two integers is 10 more than 4 times t
he largest integers?
1 answer:
The smallest is 6
Three consecutive integers
X. Smallest 6
X+1. 7
X+2. Largest 8
X(X+1)= 4(X+2)+10
X^2+X= 4x+8+10
X^2+X-4x-18=0
X^2-3x-18=0
( X+3)(X-6)
X=-3. X=6
Don't use the negative
Check 6(7)= 4(8)+10
42=42
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Hi i don’t speak spanish but hi....?
A rotation around the origin of 180° and an enlargement by a scale factor of 3
+x on each side. Then -2 on each side. Then divide both sides by 6 and you have your answer
Y=3negativeX+18. y=3(-x)+18. I hope I helped.
