Ask question

Ask question

All categories

3 years ago

8

To solve the inequality 9x >-4, the inequality sign must be reversed.

2 answers:

Anna35 [415]3 years ago

7 0

Answer:

false

Step-by-step explanation:

you only need to reverse the sign when you are dividing by a negative number

taurus [48]3 years ago

4 0

Answer: False?

Step-by-step explanation:

You might be interested in

Please help!!!! I'm so confused :\ I'm sorry ik this is annoying

spin [16.1K]

Answer:

I believe it will be C

Step-by-step explanation:

Hope this Helped you

5 0

2 years ago

Whats the slope of the 2 points (6,-6) & (-1,-3)

Bingel [31]

$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{6}}}\implies \cfrac{-3+6}{-7}\implies -\cfrac{3}{7}$

6 0

3 years ago

Solve the equation <br> -4+-1+2+.....+x=437

aliina [53]

[2<span>] </span>x<span>. </span><span>437 is the answer

</span>

7 0

3 years ago

Read 2 more answers

Find an m > 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.

Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

$x^4-(3m+2)x^2+m^2=0$

$x^4+0x^3-(3m+2)x^2+0x+m^2=0$

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

$a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}$

$=\frac{0}{1}=0$

$\implies a=0----(1)$

$(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}$

$=\frac{-3m-2}{1}$

$3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2$

$-10b^2=-3m-2$

$\implies b^2=\frac{3m+2}{10}-----(2)$

$(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2$

$9b^4=m^2$

$9(\frac{3m+2}{10})^2=m^2$

$9(\frac{9m^2+4+12m}{100})=m^2$

$81m^2+36+108m=100m^2$

$-19m^2+108m+36=0$

$19m^2-108m-36=0$

$19m^2-114m+6m-36=0$

$19m(m-6)+6(m-6)=0$

$(19m+6)(m-6)=0$

$\implies m=-\frac{6}{19}\text{ or }m=6$

But m > 0,

Hence, the value of m is 6.

4 0

3 years ago

I HAVE ANOTHER CLASS TODAY AND NEED TO FINISH IT RIGHT NOW (MAYBE 20 MIN MAX) SOMEBODY PLEASE HELP, ME! ANY ANNOYING OR FAKE ANS

lys-0071 [83]

Answer:

|x - 5| = 2

Step-by-step explanation:

Since we are not given a zero on the number line, we do the following:

Average = midpoint between two numbers on the number line

For this number line,

Average = 3 + 7 ÷ 2

Average = 5

Next we find how many units away are each number from the middle:

3 is 2 units away from 5

7 is 2 units away from 5

Units away = 2

Let's use the formula:

|x - average| = Units away

Substitute values into equation

|x - 5| = 2

Now we solve

Solve for x over the integers:

|x - 5| = 2

Split the equation into two possible equations:

x - 5 = 2 or x - 5 = -2

Add 5 to both sides:

x = -5 + 5 = 2 + 5 or x - 5 + 5 = -2 + 5

Answer:

x = 7 or x = 3

LOOK AT THE GRAPH AND NUMBER LINE

5 0

2 years ago