3 / 1/3 dividend by 1 / 1/5

will brought 3 college textbooks one cost 32 on 45 and one cost 39 what is the average price of his books ? choose the statement

777dan777 [17]

To find the average, add the cost of each book to get a total cost, then divide the total cost by the number of books purchased.

Total cost: 32 + 45 + 39 = 116

Average cost: 116 / 3 = 38.67

4 0

3 years ago

Ok what is 297×23 (23×12) please tell me im begging you

DENIUS [597]

Answer:

297 x 23 = 6831

Step-by-step explanation:

(23 x 12) = 276

Mark Brainliest!

7 0

2 years ago

A cone has a radius of five feet and a height of 18 feet. If the radius of the cone is tripled but the volume but the volume rem

olasank [31]

Volume of a cone is 1/3 of the area of the base times the height
v=(1/3)pi*5*5*18=(1/3)pi815*15*h
h=2

4 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago

Marge cut 16 pieces of tape. Each piece is 3/8in long HOW MUCH TAPE DID SHE USE???????? meow :3

Alla [95]

To solve this, all you need to do is multiply 16 by 3/8. When you multiply a whole number by a fraction, make the whole number into a fraction by putting it over 1.

16 3
---- x ---- Multiply the numerators together and then the denominators.
1 8

(16 x 3) / (1 x 8)

48 / 8 Then divide.

She used 6 inches of tape.

3 0

2 years ago

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3 / 1/3 dividend by 1 / 1/5​

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