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2 years ago

Why is x = 4 a solution to the proportion StartFraction 14 over x EndFraction = StartFraction 56 over 16 EndFraction?

Mathematics

2 answers:

mamaluj [8]2 years ago

6 0

Answer:

D <u><em>Because if you substitute 4 into the equation for x and cross multiply, you get 224 = 224.</em></u>

Step-by-step explanation:

When you cross multiply, you get 14×16=224, and 224÷4=56.

Elena-2011 [213]2 years ago

5 0

Answer:

D because if you substitute 4 into the equation for x and cross multiply, you get 224 = 224

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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

1 year ago

14 times the difference of 8 and w

Lunna [17]

14(8-W)=0
(14*8)-(14*W)=0
112-14W=0
-112 -112
------------------- The answer is 8
-14W= -112
-14W/(-14)= -112/(-14)
W=8

5 0

2 years ago

Guys can you please help me I really dont understand algebra?

KonstantinChe [14]

Yes it is linear since it's in the standard form Ax+By = C

A = 2

B = -8

C = 16

6 0

2 years ago

Read 2 more answers

There are 92,746 seats available for fans at UGA's Sanford Stadium. Auburn University's Jordan-Hare Stadium has seating for 87,4

Anvisha [2.4K]

Given :

Number of seats at UGA's Sanford Stadium, $n_1 = 92,746$ .

Number of seats at Auburn University's Jordan-Hare Stadium, $n_2=87,451$ .

To Find :

How many more seats are there at UGA's stadium.

Solution :

Extra seats at UGA's stadium = seats at UGA's Sanford Stadium - seats at

Auburn University's Jordan-Hare Stadium

= 92,746 - 87,451

= 5295

Hence, this is the required solution.

4 0

2 years ago

Solve using square root or factoring method

OlgaM077 [116]

9x^2 + 18x + 9 = 5

9(x^2 + 2x +1) - 5 = 0

x^2 + 2x - 4 = 0

Then use the quadratic formula.

8 0

2 years ago