(x-1²) +2 (x-1) - 29 hola alguien me puede ayudar a factorizar esto doy 20 puntos!!

Mathematics

1 answer:

9966 [12]3 years ago

7 0

Answer:

(x+2x)+(−30−2) = 3x−32

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Find the length and width of a rectangle whose perimeter is 40 feet and whose area is 96 square feet.

AlekseyPX

Let the length and width be l and w, respectively. Then, perimeter = 2(l + w) = 40, and area = lw = 96. In other words:
l + w = 20
lw = 96
From here, we could guess and check to get that the length and width are 12 and 8, but let’s do this rigorously:
By the first equation, l = 20 - w
Substituting into the second equation:
(20 - w) * w = 96
w^2 - 20w + 96 = 0
w^2 - 20w + 100 = 4
(w - 10)^2 = 4
w - 10 = 2 or -2
w = 12 or 8
The rest is trivial.

6 0

3 years ago

A rectangle has a length that is 3 more than twice its width. If its area is 152ft^2, what is its perimeter

liberstina [14]

Answer:

$Perimeter=54ft^2$

Step-by-step explanation:

Let's start by writing what we know in mathematical terms.

A rectangle has a length that is 3 more than twice its width, means:

$L-3 = 2W\\L*W = 152$

Now all we have to do is solve for one of these values. I'll choose W.

Rewrite the equation:

$L = 2W + 3$

Input that information into our second equation and solve:

$W*(2W + 3) = 152\\2W^2+3W=152\\2W^2+3W-152=0$

Find the two W values by factoring the equation (note that the Width can't be negative because you can't have a negative rectangle):

$2W^2+3W-152=0\\(2W+19)(W-8)=0\\\\W=-\frac{19}{2}\\W=8$

We pick the positive value 8 and plug it into our original equation to find Length:

$L = 2W + 3\\L=2(8)+3\\L=19$

Finally, after all that, we can use the formula of a perimeter using our newly found Length and Width values (remember not to forget "ft^2" when we get our answer):

$2L+2W\\2(19)+2(8)\\Perimeter=54ft^2$