For an inscribed angle like angle AHB, the measure will be half of the intercepted arc which we can see is 90 degrees.. therefore the measure of angle AHB is 45 degrees.
Answer:
i think the answer is 18.15
Step-by-step explanation:
The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st
Step-by-step explanation:
Parallel lines have same slopes and different y-intercepts
To find which equation would graph a line parallel to 3y = x + 5
1. Put the equation in the form of y = mx + c
2. m is the slope of the line and c is the y-intercept
3. Look for the equation which has the same values of m and different
values of c
∵ 3y = x + 5
- Divide each term of the equation by 3 to put the equation in the
form of y = mx + c
∴ y =
x + 
∴ m = 
∴ c = 
The first answer:
∵ 3y = x + 1
- Divide each term of the equation by 3
∴ y =
x + 
∴ m = 
∴ c = 
∵ The two equations have same slope m = 
∵ The two equations have different y-intercepts c = 
and c = 
∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines
The equation 3y = x + 1 would graph a line parallel to 3y = x + 5
Learn more:
You can learn more about slope of a line in brainly.com/question/12954015
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3844 x 10²
all you need to do is think about the 10th power
Where a, b, and c are real numbers and a ≠ 0 .
The quadratic term is ax
2
, the linear term is
bx, and the constant term is c. Quadratic
functions have degree two. The graph of a
quadratic function is called a parabola. If
a < 0, then the parabola opens downward,
like function g. If
a > 0, then the parabola
opens upward like function f. If
the parabola opens upward, then
the vertex is the point whose yvalue
is the minimum value of f.
If the parabola opens downward,
then the vertex is the point
whose y-value is the maximum
value of f. The vertical line that
goes through the vertex is called
the axis of symmetry of the
parabola.