<span><span>The derivative is:
y= 4<span>(<span><span>x</span></span></span></span></span>³<span><span><span><span>−<span>x</span></span></span></span></span>²<span><span><span><span>+x+1</span>)</span><span>e</span></span></span>×<span><span><span>/</span></span><span><span>(<span><span>x</span></span></span></span></span>²<span><span><span><span>+1</span>)</span></span></span>²
Answer:
Four consecutive integers whose sum is 114 are 27 , 28 , 29 , 30 .
Step-by-step explanation:
Consecutive numbers are numbers having each number is one more than the previous number. like consecutive number of 2 is 3 .
We have to four consecutive integers whose sum is 114.
Let integers be in the form x , (x+1) , (x+2) , (x+3)
Given : Sum of integers be 114.
thus, x + (x+1) + (x+2) + (x+3) = 114
⇒ 4x +6 = 114
⇒ 4x = 114 -6
⇒ 4x = 108
⇒
⇒ x = 27
Thus, integers are,
x = 27
(x+1) = 27 + 1 = 28
(x+2) = 27 +2 = 29
(x+3) = 27 +3 = 30
Thus, four consecutive integers whose sum is 114 are 27 , 28 , 29 , 30 .
Answer:
g(x) = |x+3|
Step-by-step explanation:
Within the parentheses, it'll go left or right, outside of it, it'll go up or down
(24 - 18) = 6
(32/4) = 8
6 x 8 = 48
48 is your answer
first do the parethensis, and then multiply
follow PEMDAS
hope this helps