Answer
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Siddharta7
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Step-by-step explanation:
Given,
BAD and ADC are right angles[angles in semicircle is 90]
AD is common to both triangles.
=> ∠BAD = ∠CDA[angles in semicircle is 90°]
=> ∠ABO = ∠DCA[angles in same segment are equal]
∴ ΔABD and ΔDCA are congruent. ----- ASA
(or)
BD = CA[diameters of the circle]
=> ∠BAD = ∠CDA[angles in semicircle is 90°]
AD is common to both triangles.
ΔABD and ΔDCA are congruent triangles. ----- RHS
(or)
BD = CA[diameter of circle]
AD is common.
=> ∠ADB = ∠CAD[base angles of an isosceles triangle are equal]
∴ ΔABD and ΔDCA are congruent triangles. ------ SAS
Hope it helps!
