I really hope this helps this is what my teacher said to do in the type of problem
First write both vectors in terms of their horizontal and vertical components.
G = (40.3 m)(cos(-35.0º) x + sin(-35.0º) y)
G = (33.0 x - 23.1 y) m
(where x and y are the unit vectors that point in the positive horizontal and vertical directions, respectively)
H = (63.3 m)(cos 270º x + sin 270º y)
H = (-63.3 y) m
Then the vector sum is
G + H = (33.0 x - 86.4 y) m
which has a magnitude of
|| G + H || = √[33.0^2 + (-86.4)^2] = 92.5 m
The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.
<u>Step-by-step explanation</u>:
ABCD is a quadrilateral with their opposite sides are congruent (equal).
The both pairs of opposite sides are given as AB = 3 + x
, DC = 4x
, AD = y + 1
, BC = 2y.
- AB and DC are opposite sides and have same measure of length.
- AD and BC are opposite sides and have same measure of length.
<u>To find the length of AB and DC :</u>
AB = DC
3 + x = 4x
Keep x terms on one side and constant on other side.
3 = 4x - x
3 = 3x
x = 1
Substiute x=1 in AB and DC,
AB = 3+1 = 4
DC = 4(1) = 4
<u>To find the length of AD and BC :</u>
AD = BC
y + 1 = 2y
Keep y terms on one side and constant on other side.
2y-y = 1
y = 1
Substiute y=1 in AD and BC,
AD = 1+1 = 2
BC = 2(1) = 2
Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.
Answer:
The answer would be D. 5
Step-by-step explanation:
The answer to the problem is going to be 3
