Check the picture below.
make sure your calculator is in Degree mode.
Answer:
x = - 1 ± 2i
Step-by-step explanation:
we can use the discriminant b² - 4ac to determine the nature of the roots
• If b² - 4ac > , roots are real and distinct
• If b² - 4ac = 0, roots are real and equal
• If b² - ac < 0, roots are not real
for x² + 2x + 5 = 0
with a = 1, b = 2 and c = 5, then
b² - 4ac = 2² - (4 × 1 × 5 ) = 4 - 20 = - 16
since b² - 4ac < 0 there are 2 complex roots
using the quadratic formula to calculate the roots
x = ( - 2 ±
) / 2
= (- 2 ± 4i ) / 2 = - 1 ± 2i
Hi! for x, you need to do 2x-8 = x+17 and solve, because since b is the midpoint, ab and bc would be congruent.
2x-8 = x+17
1x-8 = 17
1x = 25
x = 25
in order to find ab, you plug in the x into the expression.
ab = 2x-8
ab = 2(25)-8
ab = 42
do the same for bc:
bc = x + 17
bc = 25 + 17
bc = 42
and for ac, combine the two expressions and plug in the value for x.
ac = ab + bc
ac = 2x-8 + x+17
ac = 2(25)-8 + 25+17
ac = 84
i hope this helped! have a good day/night :)
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