Order from least to greatest. Change each fraction into decimal by dividing.
5/8 = 0.625
1/3 = ~0.33
17/24 = ~0.71
The order is: 0.33, 0.625, 0.71, or
First (least): 1/3
Second: 5/8
Third (most): 17/24
hope this helps
Answer:
C
Step-by-step explanation:
Remember that if s(t) is a position function then:
is the velocity function and
is the acceleration function.
So, to find the acceleration, we need to solve for the second derivative of our original function. Our original function is:

So, let's take the first derivative first with respect to t:
![\frac{d}{dt}[s(t)]=\frac{d}{dt}[t^2+4t+10]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5Bs%28t%29%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5E2%2B4t%2B10%5D)
Expand on the right:
![s'(t)=\frac{d}{dt}[t^2]+\frac{d}{dt}[4t]+\frac{d}{dt}[10]](https://tex.z-dn.net/?f=s%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5E2%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B4t%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B10%5D)
Use the power rule. Remember that the derivative of a constant is 0. So, our derivative is:

This is also our velocity function.
To find acceleration, we want to second derivative. So, let's take the derivative of both sides again:
![\frac{d}{dt}[s'(t)]=\frac{d}{dt}[2t+4]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5Bs%27%28t%29%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B2t%2B4%5D)
Again, expand the right:
![s''(t)=\frac{d}{dt}[2t]+\frac{d}{dt}[4]](https://tex.z-dn.net/?f=s%27%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B2t%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B4%5D)
Power rule. This yields:

So, our answer is C.
And we're done!
Answer: 2.5
Step-by-step explanation:
Y^3+5y^2-14y
y(y^2+5y-14)
y(y^2+7y-2y-14)
y(y(y+7)-2(y+7))
y(y-2)(y+7)
So there are infinite solutions with the only restriction being that y>2 as V>0
Answer:what we observe is that the square of the number follows a pattern: 2 1's gives 121. 3 1's gives 12321. so to get 12345678987654321 we need to get square of 9 1's(111,111,111).