What were Lamarck's ideas about evolution and why were those ideas incorrect
Answer:
hope this helps you
Explanation:
Example 1: A 20 kg object has a velocity of 4.5 m/s in the positive x direction. ... What is the momentum of a 3000 kg truck traveling at 25 m/s? 2. A 1500 kg ferryboat has a momentum of 25000 kg∙m/s. ... *A 0.01 kg bullet has a speed of 700 m/s before it strikes a 0.95 kg wooden block ... We will be going outside so please.
Answer:
0.44g
Explanation:
Given parameters:
Mass of magnesium hydroxide = 0.645g
Solution
The balanced reaction equation is shown below:
Mg(OH)₂ → MgO + H₂O
From the equation above, we see that the number of atoms are conserved.
To find the mass of magnesium oxide produced, we find the number moles of the decomposed magnesium hydroxide first:
Molar mass of Mg(OH)₂ = 24 + 2(16+1) = 58g/mol
Number of moles of Mg(OH)₂ = 
= 
= 0.011mole
Now, from the balanced equaiton, we know that:
1 mole of Mg(OH)₂ produces 1 mole of MgO
Therefore, 0.011mole of Mg(OH)₂ will produce 0.011mole of MgO
so mass of MgO = number of moles of MgO x molar mass of MgO
Molar mass of MgO = 24 + 16 = 40g/mol
mass of MgO = 0.011 x 40 = 0.44g
Answer:
is used to break reactant bonds and/or make new product bonds.
Explanation:
<em>The correct answer would be that </em><em>activation energy is used to break reactant bonds and/or make new product bonds</em><em>.</em>
The <u>activation energy is the minimum energy that must be overcome by the reactants in a reaction in other to become products</u>. In order for products to be formed, the bonds between reactants must be broken and new ones must be formed to arrive at the products. In other words, the activation energy can be seen as the energy required to break the bonds between reactants and form the bonds between products during the course of a reaction.
<em>Activation energy is required even in the presence of enzymes. The latter only catalyzes reactions by lowering the minimum energy required to break the bonds between reactants and form new ones between products</em>.
