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3 years ago

PLEASE HELP!!!!! Noble gases are often described as being very stable. Give two points to explain what this means.

Chemistry

1 answer:

Leya [2.2K]3 years ago

6 0

Answer:

Noble Gases are very stable because...

1) Noble Gases have a full octet

2) Low chemical reactivity

Explanation:

This means that is has 8 valence electrons so it won't need any more, so it is less likely to react with other substances.

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Compute the molar enthalpy of combustion of glucose (C6 H12O6 ): C6 H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2 O (g) Given that com

lana66690 [7]

Answer:

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

Explanation:

Step 1: Data given

Mass of glucose = 0.305 grams

Combustion of 0.305 grams causes a raise of 6.30 °C

Calorimeter has a heat capacity of 755 J/°C

Molar mass of glucose = 180.2 g/mol

Step 2: The balanced equation

C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)

Step 3:

ΔH = (m * C * ΔT + c(calorimeter) * ΔT)

with m = mass of the solutin = 0.305 grams

with C = heat capacity of water = 4.184 J/g°C

with ΔT = the change in temperature = 6.30 °C

with c(calorimeter) = 755 J/°C

ΔH = 0.305 * 4.184 *6.30 + 755 * 6.30 = 4764.5 J ( negative because it's exothermic)

Step 4: Calculate moles of glucose

Moles glucose = mass glucose / Molar mass glucose

Moles glucose = 0.305 grams / 180.2 g/mol

Moles glucose = 0.00169 moles

Step 5: Calculate molar enthalpy

Molar enthalpy = -4764.5 J / 0.00169 moles

Molar enthalpy = - 2819254.2 J/moles = -2819.3 kJ/moles

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

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3 years ago

Under certain conditions, the solid and liquid states of water can exist in equilibrium. How are these conditions indicated on t

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It is not a pure substance, because a solution are mixed chemicals in a way that the molecules are not bonded with one another. Thus, separating them from compounds and elements, which are pure substances.

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3 years ago

Drag each label to the correct location on the image identify the parts of the energy diagram

diamong [38]

If you would’ve attached a picture I’m sure it would’ve been a lot easier.

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In a synthesis reaction you start with 1.7L of Hydrogen how many liters of water will be produced?

jolli1 [7]

15.3 litres of water will be produced if we take 1.7 litres of Hydrogen

Explanation:

Let's take a look over synthesis reaction;

$H_{2}+ O_{2}$ $H_{2}O$

Balancing the chemical reaction;

$2H_{2} +O_{2}$ $2H_{2}O$

Thus, 2 moles of hydrogen molecules are required to form 2 moles of water molecules.

Equating the molarity;

$\frac{1.7*1}{2*2}$ = $\frac{x*1}{2*18}$

(Since, the molecular mass of hyd and water is 2 and 18 respectively)

x= $\frac{1.7*2*18}{2*2}$

x= 15.3 litres.

Thus,15.3 L of water will be produced if we take 1.7 litres of Hydrogen in a synthesis reaction.

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3 years ago