1.505X10^24 hope this helped :)
Answer:
False
Explanation:
My opinion is False and im not sure
Answer:
The attractive force is negative and MgO has a higher melting point
Explanation:
From Couloumb's law:
Energy of interaction, E = k 
where q1 and q2 are the charges of the ions, k is Coulomb's constant and r is the distance between both ions, i.e the atomic radii of the ions.
If you look at Coulomb's law, you note that in the force is negative (because q1 is negative while q2 is positive).
In addition to that, the compounds MgO and NaF have similar combined ionic radii, then we can determine the melting point trend from the amount of energy gotten
The melting point of ionic compounds is determined by 1. charge on the ions 2. size of ions. while NaF has smaller charges (+1 and -1), MgO (+2 and -2) has larger charges and greater combined atomic radii. This implies that the compound with greater force would have a higher melting point.
Hence the compound MgO would have a higher melting point than NaF.
Ti2 has 2 unpaired electrons.
Start by writing the atoms balance:

Now, determine the change of oxidation states:

has oxidation state 0, so each N has to gain 3 electrons to become

.
That, means that you need 6 electrons to balance the charges, resulting in:
And the answer is 6 mole of electrons.