Answer:
concentration in ppm of DDT = 0.011 ppm
Explanation:
since ppm of DDT =mg of DDT /Kg of solution ( or μg of DDT /g of solution) , then
concentration in ppm of DDT = 4.21 × 10⁻⁷ kg * 10⁶ mg/kg / ( 1.00 g/mL * 3.7 L * 1000 ml/L * 1 kg/1000gr) = 0.011 ppm
then
concentration in ppm of DDT = 0.011 ppm
Answer: The value of for the given reaction is .
Explanation:
The ratio of concentration of products and reactants raised to the power of their concentration is called equilibrium constant.
It is denoted by the symbol .
For example,
The expression for of this reaction is as follows.
So, by putting the respective concentrations of the species involved in the reaction it is possible to determine the value of for the given reaction.
Thus, we can conclude that the value of for the given reaction is .
Particle C is more likely to participate in the reaction than particle B.
Answer:
0.218 M of Pb(NO3)2
Explanation:
Equation of the reaction
Pb(NO3)2(aq) + 2NaCl(aq) --> PbCl2(s) + 2NaNO3(aq)
1 mole of Pb(NO3)2 reacts to precipitate 1 mole of PbCl2
Molar mass of PbCl2 = 207 + (35.5*2)
= 278 g/mol
Number of moles of PbCl2 precipitated = mass/molar mass
= 12.11/278
= 0.04356 mol
Since 0.04356 moles of PbCl2 was precipitated, therefore by stoichiometry; 0.04356 moles of Pb(NO3)2 reacted.
Molarity is defined as the number of moles of solute in 1 liter of solution.
Molarity = number of moles/volumes
= 0.04356/0.2
= 0.218 M