Answer:
This statement is sometimes true
Answer:
Hay un máximo de tres ceros en el producto de un número distinto de cero cero menor que 10 y 500
Para poder ver esto, la forma más fácil para resolver este problema es multiplicar todos los números entre 1 y 9 por 500, es decir:
01*500 = 500
2*500 = 1.000
3*500 = 1.500
4*500 = 2.000
5*500 = 2.500
6*500 = 3.000
7*500 = 3.500
8*500 = 4.000
9*500 = 4.500
Como vemos, si multiplicamos a 500 por cualquier número par, entonces obtenemos un número con tres ceros, mientras que si este es impar solamente obtenemos dos ceros
dame coronaa
Nope. Perimeter = sum of all sides
P = 20 + 11 + 20 + 11 = 62 and not 64
So, it is not possible.
The system of linear equations represents the situation is;
x + y = 125
x + y = 1255x + 8y = 775
<h3>Simultaneous equation</h3>
Simultaneous equation is an equation in two unknown values are being solved for at the same time.
let
- number of quick washes = x
- number of premium washes = y
x + y = 125
5x + 8y = 775
From equation (1)
x = 125 - y
5x + 8y = 775
5(125 - y) + 8y = 775
625 - 5y + 8y = 775
- 5y + 8y = 775 - 625
3y = 150
y = 150/3
y = 50
x + y = 125
x + 50 = 125
x = 125 - 50
x = 75
Therefore, the number of quick washes and premium washes Monica’s school band had is 75 and 50 respectively.
Learn more about simultaneous equation:
brainly.com/question/16863577
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