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yan [13]
3 years ago
13

Adult male heights have a normal probability distribution with a mean of 70 inches and a standard deviation of 4 inches. What is

the probability that a randomly selected male is more than 70 inches tall? Enter you answer in decimal form, e.g. 0.68, not 68 or 68%.
Mathematics
2 answers:
raketka [301]3 years ago
4 0

Answer: 0.5

Step-by-step explanation:

Given : Adult male heights have a normal probability distribution .

Population mean : \mu = 70 \text{ inches}

Standard deviation: \sigma= 4\text{ inches}

Let x be the random variable that represent the heights of adult male.

z-score : z=\dfrac{x-\mu}{\sigma}

For x=70, we have

z=\dfrac{70-70}{4}=0

Now, by using the standard normal distribution table, we have

The probability that a randomly selected male is more than 70 inches tall :-

P(x\geq70)=P(z\geq0)=1-P(z

Hence, the probability that a randomly selected male is more than 70 inches tall = 0.5

Damm [24]3 years ago
4 0

Answer:

The probability that a randomly selected male is more than 70 inches tall is 0.5

Step-by-step explanation:

Mean height of adults =\mu = 70 inches

Standard deviation = \sigma = 4 inches

We are supposed to find the probability that a randomly selected male is more than 70 inches tall i.e. P(x>70)

Formula: Z=\frac{x-\mu}{\sigma}

Z=\frac{70-70}{4}

Z=0

So, p value at z=0 is 0.5

So, P(x>70)=1-P(x<70)=1-0.5 =0.5

Hence the probability that a randomly selected male is more than 70 inches tall is 0.5

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