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otez555 [7]
3 years ago
8

Three numbers form an arithmetic sequence whose

Mathematics
1 answer:
Airida [17]3 years ago
8 0

Let <em>x</em> be the first number in the sequence. Then the first three numbers are

{<em>x</em>, <em>x</em> + 3, <em>x</em> + 6}

The next sentence says that the sequence

{<em>x</em> + 1, <em>x</em> + 9, <em>x</em> + 25}

is geometric, which means there is some fixed number <em>r</em> for which

<em>x</em> + 9 = <em>r</em> (<em>x</em> + 1)

<em>x</em> + 25 = <em>r</em> (<em>x</em> + 9)

Solve for <em>r</em> :

<em>r</em> = (<em>x</em> + 9)/(<em>x</em> + 1) = (<em>x</em> + 25)/(<em>x</em> + 9)

Solve for <em>x</em> :

(<em>x</em> + 9)² = (<em>x</em> + 25) (<em>x</em> + 1)

<em>x</em> ² + 18<em>x</em> + 81 = <em>x</em> ² + 26<em>x</em> + 25

8<em>x</em> = 56

<em>x</em> = 7

Then the three numbers are

{7, 10, 13}

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