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Naddik [55]
3 years ago
14

!!! ANSWER THE PROBLEM ASAP !!!

Mathematics
1 answer:
VashaNatasha [74]3 years ago
8 0

Answer:

Not defined

Step-by-step explanation:

An educated guess:)

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3. WEATHER On a cold January day,
erma4kov [3.2K]

Answer: -9 + 21 = t    t = 12°C.

Step-by-step explanation: For this problem lets have t be equal to the original temperature in the beginning of the day. The equation -9 + 21 = t represents this situation because it states that if we add the degrees that dropped to the current degrees  it will give us our original degrees.

Solve.

-9 + 21 = t (Simply add -9 + 21) -9 + 21 = (+12)

12 = t

So, the original degrees in the beginning of the day was 12°C.

3 0
3 years ago
Volume of cylinders and cones
VMariaS [17]

Answer:

V=π r2h=cylinder

V=πr2 h/3 =cone

Step-by-step explanation:

8 0
3 years ago
Number 18 pppllleeeaaassse hheellp
DanielleElmas [232]
I wish i could help, this is some tricky stuff haha
4 0
4 years ago
i will rate you brainliest// What is the interquartile range (IQR) of {5.8, 8.5, 9.9, -0.8, -1.3, 2.3, 7.4, -1.9}?
Ipatiy [6.2K]

Answer

arrange the element in increasing order

-1.9, -1.3, -0.8, 2.3, 5.8, 7.4, 8.5, 9.9

interquatile = Q3 - Q1

=  \frac{7.4 + 8.5}{2} -  \frac{ - 1.3 - 0.8}{2}

= 7.95  + 1.05

= 9

3 0
4 years ago
During a two-hour period, the temperature in a city dropped from a high of 51°F to a low of −11°F. What was the range of the tem
Likurg_2 [28]

you have to take 51 plus 11 and add it up. then your answer should be 62 degrees different.

6 0
3 years ago
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