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valkas [14]
2 years ago
14

Given parallelogram JKLM, complete the following statements.

Mathematics
1 answer:
olganol [36]2 years ago
6 0

Answer: the first 3 are 20, 5, 43. I dont know the others though

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What is the area of the triangle in the diagram?
FromTheMoon [43]

Answer:

The areaof a triangleis L×W

Step-by-step explanation:

Where is the triangle?

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Factor 16x4 - 4y2<br><br> A) (x + 4y)(x - 4y)<br> B) 4(2x2 + y)(2x2 - y)
Alex73 [517]

Step-by-step explanation:

16 {x}^{4}  - 4 {y}^{2}  \\  {4}^{2}  {x}^{4}  -  {2}^{2} {y}^{2}  \\ {4}^{2}  {x}^{2}  \times  {x}^{2}  -  {2}^{2}  {y}^{2}  \\ (4 {x}^{2}  - 2y)(4 {x}^{2}  - 2y)

6 0
3 years ago
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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard
avanturin [10]

Answer:

There is a 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard deviation of 2503 miles.

This means that \mu = 33208, \sigma = 2503.

What is the probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct?

This is the pvalue of Z when X = 33208+633 = 33841 subtracted by the pvalue of Z when X = 33208 - 633 = 32575

By the Central Limit Theorem, we have t find the standard deviation of the sample, that is:

s = \frac{\sigma}{\sqrt{n}} = \frac{2503}{\sqrt{49}} = 357.57

So

X = 33841

Z = \frac{X - \mu}{\sigma}

Z = \frac{33841 - 33208}{357.57}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

X = 32575

Z = \frac{X - \mu}{\sigma}

Z = \frac{32575- 33208}{357.57}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384.

This means that there is a 0.9616 - 0.0384 = 0.9232 = 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

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Andre45 [30]

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Step-by-step explanation:

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If you drive 130 miles and it takes you Two hours and six minutes and then you drive back on the same route but it takes you two
Vilka [71]
You can gain it by taking an hr and thirty min trip and on the way back takes hr and forty five min. That is how you gain your precious time back!!!✍️☃️⚽️
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