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Triss [41]
3 years ago
14

5/6,1/3 common denominator

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
5/6 and 2/6 are the common denominators
9966 [12]3 years ago
5 0
5/6, 2/6 you multiply 1/3 by 2 so 1x2 is 2 and 3x2 is 6 so your common Denominator is 5/6, 2/6
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Plz help
Len [333]
52x38=1976, 1976 is the answer
5 0
3 years ago
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
Read 2 more answers
What is the explicit formula for this arithmetic sequence?<br>3,9,15,21,27​
denis-greek [22]

Answer:

Step-by-step explanation:

Formula is to add 6. As you can see: 3+6=9; 9+6=15; 15+6=21 and 21+6=27.

I hope this was helpful.

8 0
3 years ago
Read 2 more answers
What does it equal? And how do you know that
zvonat [6]
You can cancel if the top and bottom are both multiplication and they have common factors.

Don't forget to vote brainliest and follow me!!!

4 0
3 years ago
In a survey of 12 people, it was found that an average of $36 was spent on their child's last birthday gift with a standard devi
Nataliya [291]

Answer:

(27.3692 ; 44.6308)

Step-by-step explanation:

Mean, xbar = 36

Standard deviation, s = 11

Sample size, n = 12

Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718

Confidence interval :

Xbar ± Margin of error

Margin of Error = Tcritical * s/sqrt(n)

Margin of Error = 2.718 * 11/sqrt(12) = 8.6308

Confidence interval :

Lower boundary : 36 - 8.6308 = 27.3692

Upper boundary : 36 + 8.6308 = 44.6308

(27.3692 ; 44.6308)

3 0
3 years ago
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