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aleksklad [387]
3 years ago
5

An anagram of a string is another string with the same characters in the same frequency, in any order. For example 'ab', 'bca, a

cb), 'bac', 'cba, 'cab' are all anagrams of the string 'abc'. Given two arrays of strings, for every string in one list, determine how many anagrams of it are in the other list. Write a function that receives dictionary and query, two string arrays. It should return an array of integers where each element i contains the number of anagrams of queryll that exist in dictionary.
Computers and Technology
1 answer:
nlexa [21]3 years ago
4 0

Answer:

from collections import Counter

def anagram(dictionary, query):

   newList =[]

   for element in dictionary:          

       for item in query:

           word = 0

           count = 0

           for i in [x for x in item]:

               if i in element:

                   count += 1

                   if count == len(item):

                       newList.append(item)

   ans = list()

   for point in Counter(newList).items():

       ans.append(point)

   print(ans)        

mylist = ['jack', 'run', 'contain', 'reserve','hack','mack', 'cantoneese', 'nurse']

setter = ['ack', 'nur', 'can', 'con', 'reeve', 'serve']

anagram(mylist, setter)

Explanation:

The Counter class is used to create a dictionary that counts the number of anagrams in the created list 'newList' and then the counter is looped through to append the items (tuple of key and value pairs) to the 'ans' list which is printed as output.

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Answer:

Follows are the matching to this question:

Explanation:

Column  A            Column B

     1                           c

     2                          d

     3                          b

     4                          a

Description of the matching:

  • In 1(Acid) the correct choice is (c) because the acid (HCl) dissociates to both the H+ ion and the Cl- ion as a solution.  
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Answer:

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The worst case scenario is when you find the value at the last array position. So, in a N-length array, the information is at position N. This means that the worst case running time of a linear search is O(N).

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3 years ago
Read 2 more answers
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