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Mars2501 [29]
3 years ago
13

Question 24… please someone help thank you!

Mathematics
2 answers:
den301095 [7]3 years ago
6 0

Area of the middle square = 6 x 6 = 36

Area of a triangle is 1/2 x base x height:

Area = 1/2 x 6 x 6 = 18

Both triangles have a base of 6 and height of 6 so both triangles have the same area.

Total area = 36 + 18 + 18 = 72 square in.

The answer is D. 72

fredd [130]3 years ago
5 0

Answer:

72 in^2

Step-by-step explanation:

The area of the square in the middle is

A = s^2 = 6^2 = 36

The area of the triangle on the left is

A =1/2 bh = 1/2 ( 6*6) = 18

The area of the triangle on the right

A = 1/2 bh = 1/2(6*6) = 18

Add the areas together

36+18+18 = 72

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Sara was thinking of a number. Sara halves the number and gets an answer of 38.5. Form an equation with x for the information
lbvjy [14]

Answer:The equation wth x in the information can be written as

1/2 x = 38.5 , Upon solving, the number = 77

Step-by-step explanation:

Let the number Sara was thinking about be x

halving the number to get an answer = 38.5 can be expressed as

 1/2 X = 38.5

The equation with x in the information can be written as

1/2 x = 38.5

solving it becomes

1/2 x= 38.5

x = 38.5 x 2

x=77

The number Sara was thinking about = 77

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A number divided by the sum of three and four
polet [3.4K]

Answer:

(3t + 4) / (4 - r)

Step-by-step explanation:

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3 years ago
I need help with this. Thanks <br><br><br> I need to find the degree
scoundrel [369]

Answer:

  119.05°

Step-by-step explanation:

In general, the angle is given by ...

  θ = arctan(y/x)

Here, that becomes ...

  θ = arctan(9/-5) ≈ 119.05°

_____

<em>Comment on using a calculator</em>

If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.

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It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...

  Tan = Opposite/Adjacent = |y|/|x|

This is the tangent of the reference angle, which will be ...

  θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°

You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.

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Answer:

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